<span>You can start with the equations you know
a=v^2/r = (2pi*r/T)^2/r = 4pi^2r/T^2
Radius of earth (R) = 6378.1 km
Time in one day (T) = 86400 seconds
Latitude = 44.4 degrees
If you draw a circle and have the radius going out at a 44.4 degree angle above the center you can then find the r.
r=Rcos(44.4)
r=6378.1cos(44.4)
r= 4556.978198 km or 4556978 m
Now you can plug this value into the acceleration equation from above...
a= 1.8*10^8/7.47*10^9
a= .0241 m/s^2 </span>
Answer:
The surface gravity is inversely proportional to the square of the radius of the planet
Explanation:
The gravity at the surface of a planet is given by:
where
G is the gravitational constant
M is the mass of the planet
R is the radius of the planet
We see from the formula that the surface gravity is inversely proportional to the square of the radius of the planet, R.
At the Earth's surface, the value of the surface gravity is approximately 9.81 m/s^2.
The answer would be D. <span>The tortoise moved at a constant velocity throughout the race; the hare stopped to rest periodically.
Hope this helped. Good luck!</span>
Now really !
If there were some kind of treatment of the results that made them
more difficult to prove by experiment, or made them more confusing,
or made them less appealing to the public, then there would be no
reason on Earth to treat them that way.
Choice ' B ' is the only positive effect, so it's the only reason you'd
WANT to handle your findings that way.
