As stated in the statement, we will apply energy conservation to solve this problem.
From this concept we know that the kinetic energy gained is equivalent to the potential energy lost and vice versa. Mathematically said equilibrium can be expressed as


Where,
m = mass
= initial and final velocity
g = Gravity
h = height
As the mass is tHe same and the final height is zero we have that the expression is now:






Answer:

Explanation:
It is given that,
Charge on helium nucleus is 2e and its mass is 
Speed of nucleus at A is 
Potential at point A, 
Potential at point B, 
We need to find the speed at point B on the circle. It is based on the concept of conservation of energy such that :
increase in kinetic energy = increase in potential×charge

So, the speed at point B is
.
The answer to that question is c. tamod
Answer: F = 130 N
Explanation: Solution:
Convert first 27 cm to m.
27 cm x 0.01 m / 1 cm = 0.27 m
Calculate the torque using T = Fd
Derive to find force F
F = T /d
= 35 N.m / 0.27 m
= 130 N