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ipn [44]
3 years ago
11

DPLEASE HELP ME TAKE SOO LONG!! (ima fail this test) its a study guide!

Chemistry
2 answers:
8_murik_8 [283]3 years ago
5 0

It’s either b or d, maybe d?

murzikaleks [220]3 years ago
5 0

I agree with magichelp

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An atom with 4 protons and 4 neutrons Is called?
Bas_tet [7]

Answer:

i'm pretty sure it's beryllium

Explanation:

5 0
2 years ago
Read 2 more answers
If fluorine gas (F₂) occupies a volume of 45.5 L at a pressure of 850
pshichka [43]

Taking into account about the ideal gas law, the mass of fluorine gas is 63.2244 grams.

<h3>What is ideal gas law</h3>

An ideal gas is a theoretical gas that is considered to be composed of randomly moving point particles that do not interact with each other. Gases in general are ideal when they are at high temperatures and low pressures.

The pressure, P, the temperature, T, and the volume, V, of an ideal gas, are related by a simple formula called the ideal gas law:

P×V = n×R×T

where:

  • P is the gas pressure.
  • V is the volume that occupies.
  • T is its temperature. The universal constant of ideal gases R has the same value for all gaseous substances.
  • R is the ideal gas constant.
  • n is the number of moles of the gas.

<h3>Definition of molar mass</h3>

The molar mass of substance is a property defined as its mass per unit quantity of substance, in other words, molar mass is the amount of mass that a substance contains in one mole.

<h3>Mass of fluorine gas</h3>

In this case, you know:

  • P= 850 mmHg= 1.11842 atm (being 1 mmHg= 0.00131579 atm)
  • V= 45.5 L
  • T =100 °C= 373 K (being 0°C= 273 K)
  • R= 0.082 \frac{atm L}{mol K}
  • n= ?

Replacing in the ideal gas law:

1.11842 atm ×45.5 L = n×0.082 \frac{atm L}{mol K}× 373 K

Solving:

n= (1.11842 atm ×45.5 L)÷ (0.082 \frac{atm L}{mol K}× 373 K)

<u><em>n= 1.6638 moles</em></u>

The molar mass of F₂ is 38 g/mole. Then you can apply the folowing rule of three: If by definition of molar mass 1 mole of the compound contains 38 grams, 1.6638 moles of the compound contains how much mass?

mass= \frac{1.6638 molesx38 grams}{1 mole}

<u><em>mass= 63.2244 grams</em></u>

Finally, the mass of fluorine gas is 63.2244 grams.

Learn more about

the ideal gas law:

brainly.com/question/4147359

molar mass:

brainly.com/question/5216907

brainly.com/question/11209783

brainly.com/question/7132033

brainly.com/question/17249726

#SPJ1

7 0
1 year ago
Information-
tekilochka [14]

Answer:

So first thing to do in these types of problems is write out your chemical reaction and balance it:

Mg + O2 --> MgO

Then you need to start thinking about moles of Magnesium for moles of Magnesium Oxide. Based on the above equation 1 mole of Magnesium is needed to make one mole of Magnesium Oxide.

To get moles of magnesium you need to take the grams you started with (.418) and convert to moles by dividing by molecular weight of Mg (24.305), this gives you .0172 moles of Mg.

The theoretical yield would be the assumption that 100% of the magnesium will be converted into Magnesium Oxide, so you would get, based on the first equation, .0172 mol of MgO. Multiplying this by the molecular weight of MgO (24.305+16) gives us .693 g of MgO.

The percent yield is what you actually got in the experiment, and for this you subtract off the total mass from the crucible mass, or 27.374 - 26.687, which gives .66 g of MgO obtained.

Percent yield is acutal/theoretical, .66/.693, or 95.24%.

I'll let you do the same for the second trial, and average percent yield is just an average of the two trials percent yield.

Hope this helps.

6 0
2 years ago
In this reaction, the covalent bonds in the molecules of hydrogen and oxygen are broken.
Westkost [7]

Answer: Endothermic

Explanation:

Bond-breaking is an endothermic process. Energy is released when new bonds form. Bond-making is an exothermic process. Whether a reaction is endothermic or exothermic depends on the difference between the energy needed to break bonds and the energy released when new bonds form.

7 0
3 years ago
Which of the following is the last step in performing a titration?
allsm [11]
The last step in performing a titration is <span>determining the concentration of an unknown base. So the answer to your question is letter B. The concentration maybe either an acid or base. The other choices are the earlier procedures in performing titration.</span>
4 0
3 years ago
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