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3 years ago

9

How much would a man on Mars weigh if he had a mass of 75 kilograms and the acceleration due to gravity on the surface of Mars i

s 3.7 m/s 2?

1 answer:

blsea [12.9K]3 years ago

6 0

Answer:

F = 75(3.7) = 277.5 ≈ 280 N

Explanation:

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S = 10 + (-4) = 6

Displacement is vector quantity

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A point charge of 4.0 µC is placed at a distance of 0.10 m from a hard rubber rod with an electric field of 1.0 × 103 . What is

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4 for the first one and 5.2 for the second one.

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Read 2 more answers

One end of a horizontal spring with force constant 76.0 N/m is attached to a vertical post. A 5.00-kg can of beans is attached t

Jobisdone [24]

Answer:

a. The speed is 2.39 m/s

b. The acceleration of the block is 10.2 $\frac{m}{s^{2} }$

Explanation:

First, we have to do the energy balance where we consider two states, the first where the spring remains still and the second when it is stretched 0.400m:

$K_{1} +U_{1}+W_{ext}=K_{2}+U_{2}\\K_{1}=0\\U_{1}=\frac{1}{2} kx^{2} _{1} =0\\W_{ext}=F$ Δx= $(0.400m)\\$

W_{ext}=20.4 Nm

$U_{2} =\frac{1}{2} kx^{2} =\frac{1}{2} (76.0N/m)0.400^{2}=6.08Nm\\k_{2} =\frac{1}{2}mv^{2} _{2} \\\frac{1}{2} mv^{2} _{2}=W_{ext}-U_{2}\\v_{2}=\sqrt{\frac{W_{ext}-U_{2}}{m} } \\v_{2}=\sqrt{\frac{20.4Nm-6.08Nm}{2.5kg} } \\v_{2}=2.39 \frac{m}{s}$

To determine, the acceleration we solve the following equation for a:

$F=ma\\a=\frac{F}{m} =\frac{51.0N}{5.00kg}\\a=10.2\frac{m}{s^{2} }$

8 0

4 years ago

The following objects have velocity and mass as given: Object A: m=5 kg, ⃗v=−11 ^j Object B: m=6 kg, ⃗v=5^ i +8.7 ^ j Object C:

Fofino [41]

Answer:

For object A

m = 5 kg , v= -11 j

For B object

m = 6 kg , v= 5 i +8.7 j

For object C

m = 10 kg , v= -10 i

We know that

Linear momentum P= m v kg.m/s

a) A and C

Momentum in y direction

Py=- 5 x 11 j= - 55 j kg.m/s

Momentum in x direction

Px=- 10 x 10 j= - 100 i kg.m/s

b) B and C

Momentum in y direction

Py=6 x 8.7 j= 52.2 j kg.m/s

Momentum in x direction

Px=( 6 x 5 - 10 x 10 ) i = - 70 i kg.m/s

c) A ,B and C

By using data of a and b

Momentum in y direction

Py= 6 x 8.7 - 5 x 11 j= -2.8 j kg.m/s

Momentum in x direction

Px= 6 x 5 -10 x 10 i = -70 i kg.m/s

4 0

3 years ago

A person swims to the other end of a 20m long pool and back. What is their displacement?

mafiozo [28]

Answer:

Zero

Explanation:

It is given that,

A person swims to the other end of a 20m long pool and back.

We need to find his displacement.

Displacement = shortest path covered

He reaches at the same position as from where he has started. It means the shortest path covered is equal to 0 i.e. his displacement is zero.

3 0

3 years ago