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andre [41]
3 years ago
11

I need help on this

Physics
1 answer:
ZanzabumX [31]3 years ago
6 0
What is the question asking?
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Consider a system to be two train cars traveling toward each other. What is the total momentum of the system before the train ca
Brut [27]

Let say the two train cars are of masses m_1 and m_2

now if the speed of two cars are v_1 and v_2

then we can say that the momentum of two cars before they collide is given by

P = m_1v_1 - m_2v_2

here two cars are moving in opposite direction so we can say that the net momentum is subtraction of two cars momentum.

Now since in these two car motion there is no external force on them while they collide

So the momentum of two cars are always conserved.

hence we can say that the final momentum of two cars will be same after collision as it is before collision

P = m_1v_1 - m_2v_2

5 0
3 years ago
Read 2 more answers
At resonance, what is impedance of a series RLC circuit? less than R It depends on many other considerations, such as the values
denis23 [38]

Answer:

at resonance impedence is equal to resistance and quality factor is dependent on R L AND C all

Explanation:

we know that for series RLC circuit impedance is given by

Z=\sqrt{R^2+\left ( X_L-X_C \}right )^2

but we know that at resonance X_L=X_C  

putting  X_L=X_C in impedance formula , impedance will become

Z=R so at resonance impedance of series RLC is equal to resistance only

now quality factor of series resonance is given by

Q=\frac{\omega L}{R}=\frac{1}{\omega CR}=\frac{1}{R}\sqrt{\frac{L}{C}}  so from given expression it is clear that quality factor depends on R L and C

3 0
3 years ago
Which piece of evidence did Alfred Wegener use to develop the theory of continental drift?
Eduardwww [97]
The right answer for the question that is being asked and shown above is that: "A.tectonic activity concentrated in certain areas." A piece of evidence did Alfred Wegener use to develop the theory of continental drift is that <span>A.tectonic activity concentrated in certain areas</span>
3 0
3 years ago
A 2.5 kg tribble is placed in a bucket and whirled in a 1.4 m radius vertical circle at a constant tangential speed. If the forc
Over [174]

Given that,

Mass of a tribble, m = 2.5 kg

Radius, r = 1.4 m

The force on the tribble from the bucket does not exceed 10 times its weight.

To find,

The maximum tangential speed.

Solution,

The force acting on the tribble is equal to the centripetal force.

F = 10mg

The formula for the centripetal force is given by :

F=\dfrac{mv^2}{r}

v is maximum tangential speed

v=\sqrt{\dfrac{Fr}{m}} \\\\v=\sqrt{\dfrac{mgr}{m}} \\\\v=\sqrt{{10gr}} \\\\v=\sqrt{10\times 9.8\times 1.4} \\\\v=11.7\ m/s

So, the maximum tangential speed is 11.7 m/s.

8 0
3 years ago
Jimothy is riding his bike to his friend's house. He decides to see how fast he can go, and starts pedaling as hard as he can. H
german

Answer:

Final velocity, V = 11.5m/s

Explanation:

Given the following data;

Initial velocity, U = 2.5m/s

Acceleration, a = 1.5m/s²

Time, t = 6secs

To find the final velocity, we would use the first equation of motion

V = U + at

Substituting into the equation, we have

V = 2.5 + 1.5*6

V = 2.5 + 9

Final velocity, V = 11.5m/s

6 0
2 years ago
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