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Elina [12.6K]
4 years ago
12

Name 3 sources of co2

Chemistry
1 answer:
Veronika [31]4 years ago
4 0

Answer: There are both natural and human sources of carbon dioxide emissions. Natural sources include decomposition, ocean release and respiration. Human sources come from activities like cement production, deforestation as well as the burning of fossil fuels like coal, oil and natural gas.

Explanation:

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Write a balanced chemical equation for the standard formation reaction of solid calcium hydroxide .
AveGali [126]

Calcium Hydroxide (Ca(OH)2) can actually be formed by the reaction of Calcium Oxide (CaO) with water (H2O). The complete balanced chemical reaction is:

<span>CaO  +  H2O  -->  Ca(OH)2</span>

 

<span>The subscript 2 in (OH) means that there are 2 O and 2 H on the product side. Hence, the equation is balanced already.</span>

3 0
3 years ago
Calculate the density of an object with a mass of 3.8 g, that when placed in a 10.0 mL graduated cylinder with an initial volume
Arturiano [62]

Answer : The density of an object is 0.93 g/mL

Explanation : Given,

Mass of an object = 3.8 g

Initial volume = 4.5 mL

Final volume = 8.6 mL

First we have to calculate the volume of an object.

Volume of an object = Final volume - Initial volume

Volume of an object = 8.6 mL - 4.5 mL

Volume of an object = 4.1 mL

Now we have to calculate the density of an object.

Formula used:

\text{Density}=\frac{\text{Mass of an object}}{\text{Volume of an object}}

Now putting all the given values in this formula, we get:

\text{Density}=\frac{3.8g}{4.1mL}

\text{Density}=0.93g/mL

Therefore, the density of an object is 0.93 g/mL

3 0
3 years ago
For a particular reaction, ΔH⁰ = − 46.7 kJ/mol and ΔS⁰ = − 123.8 J / (mol ⋅ K). Assuming these values change very little with te
PilotLPTM [1.2K]

Answer:

T = 377.2 K, Less than

Explanation:

The thermodynamic quantity used in predicting whether a reaction is spontaneous or not is the gibbs free energy.

It's relationship with ΔH⁰ and ΔS⁰ is given as;

ΔG° = ΔH° - TΔS°

Basically, a negative value of ΔG° means the reaction is spontaeneous.

To obtain the calculated vale of T,

ΔS° = ΔH°/T

T = ΔH° / ΔS°

T = 377.2 K

Let's calculate the value of ΔG° at that temperature.

ΔG° = ΔH° - TΔS°

ΔG° =  − 46700 - 377.2(− 123.8)

ΔG°  = 0 (approximately, values are due to the rounding off)

At ΔG°  = 0 the reaction is at equilibrium.

To find if the reaction is spontaneous at lower or hugher temperature than the calculated temperature, we would be substituting the value of T with a smaller (random) value and also a larger (random) value.

Larger T (390K)

ΔG° = ΔH° - TΔS°

ΔG° =  − 46700 - 390(− 123.8)

ΔG°  = - 46700 + 48,282

ΔG° = 1582 J/mol

Smaller T (350K)

ΔG° = ΔH° - TΔS°

ΔG° =  − 46700 - 350(− 123.8)

ΔG°  = - 46700 + 43330

ΔG° = -3370J/mol

This means the temperature would be lesser than the calculated value for it to be spontaneus.

8 0
3 years ago
fbubduyabdubdubwudb8bndwibdiwqbdiwbidbqiydbqidbiqbd use this to get points fffffffffffffff ffffffff f f f f ffdf eo fje fje wfoj
kirza4 [7]

Answer:

lma.o

tysm for the points!

Explanation:

Have good day (or night)!  

:)

6 0
3 years ago
Describe maritime tropacal air masses
enyata [817]

Answer:

Okay I will, Maritime tropical (mT) air masses are warm, moist, and usually unstable. Some maritime tropical air masses originate in the subtropical Pacific Ocean, where it is warm and air must travel a long distance over water. These rarely extend north or east of southern California.

got it

8 0
3 years ago
Read 2 more answers
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