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2 years ago

A small mailbag is released from a helicopter that is descending steadily at 2.00 m/s. After 3.00 s.

Physics

1 answer:

Misha Larkins [42]2 years ago

4 0

Answer:

Explanation:

Initial velocity of mailbag u = 2 m/s

acceleration downwards a = g = 9.8 m/s²

time t = 3 s

a ) final velocity v = ?

v = u + at

= 2 + 9.8 x 3

= 31.4 m /s

b )

s = ut + 1/2 g t²

s is relative displacement of mailbag

u = relative initial velocity of mailbag = 0

relative acceleration = g = 9.8 m /s²

time t = 3 s

s = 0 + 1/2 x 9.8 x 3²

= 44.1 m

relative displacement of mailbag = 44.1 m .

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3 years ago

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In the periodic table, Elements are represented with their respected symbols. Above the symbol is the elements atomic number which is equal to the number of protons in each atom. Below the symbol is the mass number of that element which is roughly equal to the sum of neutrons and protons of that atom.

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Number of neutrons = mass number - atomic number = 122 - 51

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