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Nostrana [21]
3 years ago
6

Tris has a molecular weight of 121 g/mol. How many grams of Tris would you need to make 100 mL of a 100 mM solution of Tris

Chemistry
1 answer:
Zepler [3.9K]3 years ago
8 0

Answer:

1.21 g of Tris

Explanation:

Our solution if made of a solute named Tris

Molecular weight of Tris is 121 g/mol

[Tris] = 100 mM

This is the concentration of solution:

(100 mmoles of Tris in 1 mL of solution) . 1000

Notice that mM = M . 1000  We convert from mM to M

100 mM . 1 M / 1000 mM = 0.1 M

M = molarity (moles of solute in 1 L of solution, or mmoles of solute in 1 mL of solution). Let's determine the mmoles of Tris

0.1 M = mmoles of Tris / 100 mL

mmoles of Tris = 100 mL . 0.1 M → 10 mmoles

We convert mmoles to moles → 10 mmol . 1mol / 1000mmoles = 0.010 mol

And now we determine the mass of solute, by molecular weight

0.010 mol . 121 g /mol = 1.21 g

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An insulated container contains 0.3 kg of water at 20 degrees C. An alloy with a mass of 0.090 kg and an initial temperature of
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Answer:

The specific heat of the alloy is 2.324 J/g°C

Explanation:

<u>Step 1:</u> Data given

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⇒ ΔT(water) = The change of temperature = T2 - T1 = 25 - 20 = 5 °C

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If the volume of two containers stays the same , and one containers temperature is lowered, what happens to the pressure in the
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Gay-Lussacs law states that pressure is directly proportional to temperature at constant volume.
in this case the volumes of the 2 containers remain the same therefore volume is constant.
P/ T = k
where P - pressure, T - temperature and k - constant 
when temperature decreases the pressure too decreases and vice versa.
if temperature of one container is lowered the pressure also reduces.
since one containers temperature is lowered the pressure in that container reduces. 

answer is when temperature is lowered, pressure too is lowered. 
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3 years ago
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