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viktelen [127]
3 years ago
14

A student pulls out his or her chair in order to sit down. The student pulls the chair 0.75 m with a force of 20 N. How much wor

k does he or she do on the chair?
Physics
1 answer:
IRINA_888 [86]3 years ago
3 0
Work = Force x displacement
Force= 20N
Displacement= 0.75m

W= 20(0.75)
W= 15 Nm
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Sergeeva-Olga [200]

Answer:b

Explanation:

Given

Woman earn 50% more than her husband

Total sum of their money is =\$ 2500

Suppose man earns \$ P

so women earns P+0.5 P=P(1+0.5)=1.5 P

Sum of their money is

P+1.5 P=2500

P=\$ 1000

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6 0
3 years ago
At a distance of 14.0 m from a point source, the intensity level is measured to be 80 dB. At what distance from the source will
Ivan

Answer:

d_2=19.8m

Explanation:

The problem can be solved easily, because the relationship between intensities I_1 and I_2 at distances d_1 and d_2 respectively can be written as:

\frac{I_2}{I_1} =\frac{d_1^2}{d_2^2}

Where:

I_1=Intensity\hspace{3}1\\I_2=Intensity\hspace{3}2\\d_1=Distance\hspace{3}1\\d_2=Distance\hspace{3}2

In this case:

I_1=80dB\\I_2=40dB\\d_1=14m\\d_2=?

Solving for d_2

d_2=\sqrt{\frac{d_1^2 *I_1}{I_2} } =\sqrt{\frac{14^2*80}{40} } =\sqrt{392} =19.79898987m\approx19.8m

8 0
3 years ago
Read 2 more answers
describe how acceleration and velocity are related and specify if these are scalar and vector quantities
vitfil [10]

Velocity is the rate of change in distance over change in time, this can be written as:

v = Δd / Δt

While acceleration is the rate of change in velocity over change in time, this is written as:

a = Δv / Δt

 

<span>Both quantities are vector quantities because negative values means that the acceleration or velocity is acting on the opposite direction.</span>

8 0
3 years ago
Where does the energy of water at the top of the waterfall come from?
Vinil7 [7]

At the top of the waterfall, the water is higher in the gravitational field of the Earth and has gravitational potential energy. When it falls, the potential energy turns into kinetic energy.

6 0
3 years ago
Find the x-component of this<br> vector:<br> 15.3 m<br> 65.0°<br> Please help!
Harrizon [31]

Given :

Magnitude of vector, v = 15.3 m

Angle of vector from horizon, \theta = 65^o .

To Find :

The x - component of the given vector.

Solution :

We know, a vector is given by :

\vec{v} = vsin\ \theta \hat{i} + v cos \ \theta \hat{j}\\

Now, the x - component is :

\vec{v_x} = vcos\ \theta \hat{j}\\\\\vec{v_x} = 15.3 \times cos\ 65^o  \hat{j}\\\\\vec{v_x} = 15.3 \times 0.42\ \hat{j}\\\\\vec{v_x} = 6.426\  \hat{j}

Hence, this is the required solution.

4 0
3 years ago
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