Answer:
3.214 m
Explanation:
Here object is moving in a constant acceleration. Then we can use motion equations to find the total distance
V² = U² + 2as
0 = 1.5² + 2×-0.35 × s
s = 3.214 m
symbols has usual meanings.
90.2 m/s. A rock dropped from rest after it has falling for 9.2 seconds will have a velocity of 90.2m/s.
The bodies left in free fall increase their speed (downwards) by 9.8 m/s² every second. The acceleration of gravity is the same for all objects and is independent of the masses of these. In the free fall the air resistance is not taken into account.
v = g*t
v = (9.8m/s²)(9.2s) = 90.2 m/s
Answer:
Explanation:
5 C = 278 K
25 C = 298 K
V1 / T1 = V2 / T2
1.5L / 278 K = V2 / 298 K
V2 = (1.5L * 298) / 278
V2 = 1.61 L
-- There's no limit to the distance of gravitational forces.
There's gravitational force between Pluto and the lint in your
pocket ... not much, but it's there, and it can be calculated.
So there's ALWAYS gravitational force between the Earth and the
spaceship, AND ALSO between the Moon and the spaceship.
Even before it's ever launched !
-- The Earth has about 80 times as much mass as the Moon has,
so you have to be much closer to the Moon before the gravitational
forces in each direction are equal.
BEFORE the shot, the cannon is just sitting there with the ball inside.
Their combined momentum is zero.
Momentum is conserved, so their combined momentum has to be
zero AFTER the shot too.
Whatever momentum the ball has in one direction, the cannon
must have the same momentum in the other direction.
Momentum = (mass) x (speed)
Momentum of the ball = (6 kg) x (200 m/s) = 1,200 kg-m/s
Momentum of the cannon =
(2,000 kg) x (speed) = 1,200 kg-m/s
Divide each side by (2,000 kg)
speed = (1,200 kg-m/s) / (2,000 kg)
= 0.6 m/s
That's where the recoil of any gun comes from. The same
momentum as the bullet has, but in the opposite direction.
