Proving a parallelogram side theorem.
2 answers:
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Let's call:
f = price of 1 cup of dried fruit
a = price of 1 cup of almonds
In order to build the linear system, you need to consider that the total price of a bag is given by the sum of the price of cups times the number of cups in each bag, therefore:
Solve for a in first equation:
a = (6 - 3f) / 4
Then substitute in the second equation:
41/2 f + 6 · (6 - 3f) / <span>4 = 9
41/2 f + 9 - 9/2 f = 9
16 f = 0
f = 0
Now, substitute this value in the formula found for a:
</span>a = (6 - 3·0) / <span>4
= 3/2 = 1.5
Hence, the cups of dried fruit are free and 1 cup of almond costs 1.5$</span>
f = price of 1 cup of dried fruit
a = price of 1 cup of almonds
In order to build the linear system, you need to consider that the total price of a bag is given by the sum of the price of cups times the number of cups in each bag, therefore:
Solve for a in first equation:
a = (6 - 3f) / 4
Then substitute in the second equation:
41/2 f + 6 · (6 - 3f) / <span>4 = 9
41/2 f + 9 - 9/2 f = 9
16 f = 0
f = 0
Now, substitute this value in the formula found for a:
</span>a = (6 - 3·0) / <span>4
= 3/2 = 1.5
Hence, the cups of dried fruit are free and 1 cup of almond costs 1.5$</span>