<span>i Ace</span>hello :
let : A(-6,6) B(6,-2)
the center is w((-6+6)/2 , (6-2)/2)....(midel <span>[ AB]
w(0 ,2)
the ridus is : r = AB/2
AB = </span>√(-6-6)²+(6+2)² = √(144+64) =<span>√208/2
</span>an equation in <span>standard form equation of the circle :
</span>(x+0)²+(y-2)² = (√208/2)²=208/4 = 52
Answer:
No solution.
Step-by-step explanation:
Step 1: Write equation
-3(-x + 4) = 5 + 3(x + 1)
Step 2: Solve for <em>x</em>
- Distribute: 3x - 12 = 5 + 3x + 3
- Combine like terms: 3x - 12 = 3x + 8
- Subtract 3x on both sides: -12 ≠ 8
Here, we see that <em>x</em> has to equal no solution. No value of <em>x</em> would make the equation true.
Answer:
c
Step-by-step explanation:
Answer:
(a) Neither
(a) Perpemdicular
Step-by-step explanation:
Required
Determine the relationship between given lines
(a)

and

An equation written in form:
has the slope:

So, in both equations:


For both lines to be parallel

This is false in this case, because:

For both lines to be perpendicular

This is false in this case, because:

(b)

and

Write equations in form:


Divide by 5



Divide by 2

In both equations:


For both lines to be parallel

This is false in this case, because:

For both lines to be perpendicular

This is true in this case, because:

Cancel out 2 and 5
