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2 years ago

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6 in 24 in I don’t get this at all and I have trouble with math

1 answer:

nekit [7.7K]2 years ago

6 0

What’s the full question?

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If the endpoints of the diameter of a circle are (−6, 6) and (6, −2), what is the standard form equation of the circle?

Sergeeva-Olga [200]

<span>i Ace</span>hello :
let : A(-6,6) B(6,-2)
the center is w((-6+6)/2 , (6-2)/2)....(midel <span>[ AB]
w(0 ,2)
the ridus is : r = AB/2
AB = </span>√(-6-6)²+(6+2)² = √(144+64) =<span>√208/2
</span>an equation in <span>standard form equation of the circle :
</span>(x+0)²+(y-2)² = (√208/2)²=208/4 = 52

4 0

2 years ago

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-3(-x+4)=5+3(x+1) please help

Lostsunrise [7]

Answer:

No solution.

Step-by-step explanation:

Step 1: Write equation

-3(-x + 4) = 5 + 3(x + 1)

Step 2: Solve for <em>x</em>

Distribute: 3x - 12 = 5 + 3x + 3
Combine like terms: 3x - 12 = 3x + 8
Subtract 3x on both sides: -12 ≠ 8

Here, we see that <em>x</em> has to equal no solution. No value of <em>x</em> would make the equation true.

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3 years ago

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Someone pls help!!!!

Ray Of Light [21]

Answer:

c

Step-by-step explanation:

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3 years ago

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[12÷(9-6)]+4×6 <br>please help

Pavel [41]

The answer is 28 ez.

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2 years ago

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Given the line y = − 2 5 x + 3, determine if the given line is parallel, perpendicular, or neither. Select the correct answer fo

stiks02 [169]

Answer:

(a) Neither

(a) Perpemdicular

Step-by-step explanation:

Required

Determine the relationship between given lines

(a)

$y = -\frac{2}{5}x + 3$

and

$y = \frac{2}{5}x + 7$

An equation written in form: $y=mx + b$ has the slope:

$m \to slope$

So, in both equations:

$m_1 = -\frac{2}{5}$

$m_2 = \frac{2}{5}$

For both lines to be parallel

$m_1 = m_2$

This is false in this case, because:

$-\frac{2}{5} \ne \frac{2}{5}$

For both lines to be perpendicular

$m_1 * m_2 = -1$

This is false in this case, because:

$-\frac{2}{5} * \frac{2}{5} \ne -1$

(b)

$5y + 2x = -10$

and

$-5x + 2y = 4$

Write equations in form: $y=mx + b$

$5y + 2x = -10$

$5y = -2x +10$

Divide by 5

$y = -\frac{2}{5}x +2$

$-5x + 2y = 4$

$2y = 5x + 4$

Divide by 2

$y = \frac{5}{2}x + 2$

In both equations:

$m_1 = -\frac{2}{5}$

$m_2 = \frac{5}{2}$

For both lines to be parallel

$m_1 = m_2$

This is false in this case, because:

$-\frac{2}{5} \ne \frac{5}{2}$

For both lines to be perpendicular

$m_1 * m_2 = -1$

This is true in this case, because:

$-\frac{2}{5} * \frac{5}{2} = -1$

Cancel out 2 and 5

$-1 = -1$

6 0

2 years ago