Ask question

Ask question

All categories

3 years ago

9

Jules Verne wrote the book Twenty Thousand Leagues Under the Sea. If one league - 5.556 km and one furlong - 660.0 feet, how man

y furlongs did the Nautilus travel? (assume the twenty thousand leagues is good for 3 sig. fig.) ball park-550,000 furlong T

1 answer:

Vlad [161]3 years ago

7 0

Answer:

The Nautilus travel $5.52\times 10^5 furlongs$ .

Explanation:

Given: 1 league = 5.556 km

1 furlong = 660.0 feet

To find: 20,000 leagues = ? furlongs

Solution:

20,000 leagues = $20,000\times 5.556 km =111,120 km$

1 km = 3280.84 feet

$111,120 km= 111,120\times 3280.84 feet=364,566,940.8 feet$

If ,1 furlong = 660.0 feet.

Then, 1 foot = $\frac{1}{660.0} furlong$

$364,566,940.8 feet=364,566,940.8 \times \frac{1}{660.0}$

$=552,374.1524 furlongs\approx 5.52\times 10^5 furlongs$

You might be interested in

A sample of gas in a cylinder of volume 3.42 L at 298 K and 2.57 atm expands to 7.39 L by two different pathways. Path A is an i

lorasvet [3.4K]

Answer : The work done for path A and path B is -685.3 J and -478.1 J respectively.

Explanation :

<u>To calculate the work done for path A :</u>

First we have to calculate the moles of the gas.

$PV=nRT$

where,

$P_1$ = initial pressure of gas = 2.57 atm

$V_1$ = initial volume of gas = 3.42 L

n = moles of gas = ?

R = gas constant = 0.0821 atm.L/mol.K

T = temperature of gas = 298 K

Now put all the given values in the above formula, we get:

$PV=nRT$

$(2.57atm)\times (3.42L)=n\times (0.0821atm.L/mol.K)\times (298K)$

$n=0.359mole$

According to the question, this is the case of isothermal reversible expansion of gas.

As per first law of thermodynamic,

$\Delta U=q+w$

where,

$\Delta U$ = internal energy

q = heat

w = work done

As we know that, the term internal energy is the depend on the temperature and the process is isothermal that means at constant temperature.

So, at constant temperature the internal energy is equal to zero.

$\Delta U=0$

$q=-w$

The expression used for work done will be,

$w=-nRT\ln (\frac{V_2}{V_1})$

where,

w = work done on the system = ?

n = number of moles of gas = 0.359 mole

R = gas constant = 8.314 J/mole K

T = temperature of gas = 298 K

$V_1$ = initial volume of gas = 3.42 L

$V_2$ = final volume of gas = 7.39 L

Now put all the given values in the above formula, we get :

$w=-0.359mole\times 8.314J/moleK\times 298K\times \ln (\frac{7.39L}{3.42L})$

$w=-685.3J$

Thus, the work done of path A is, -685.3 J

<u>To calculate the work done for path B :</u>

The formula used for isothermally irreversible expansion is :

$w=-p_{ext}dV\\\\w=-p_{ext}(V_2-V_1)$

where,

w = work done

$p_{ext}$ = external pressure = 1.19 atm

$V_1$ = initial volume of gas = 3.42 L

$V_2$ = final volume of gas = 7.39 L

Now put all the given values in the above formula, we get :

$w=-p_{ext}(V_2-V_1)$

$w=-(1.19atm)\times (7.39-3.42)L$

$w=-4.72L.atm=-4.72\times 101.3J=-478.1J$

Thus, the work done of path B is, -478.1 J

7 0

2 years ago

A first-order reaction has a half-life of 20.0 minutes. Starting with 1.00 × 1020 molecules of reactant at time t = 0, how many

zalisa [80]

Half-life time of a reaction is time at which reactant concentration becomes half of its initial value.

Half-life of the first order reaction is 20 min. Rate constant can be calculated as follows:

$K=\frac{0.6932}{t_{1/2}}=\frac{0.6932}{20 min}=0.03466 min^{-1}$

The rate expression for first order reaction is as follows:

$k=\frac{2.303}{t}log\frac{A_{0}}{A_{t}}$

initial number of molecules of reactant are $10^{20}$ , time is 100 min thus, putting the values to calculate number of reactant at time 100 min,

$0.03466 min^{-1}=\frac{2.303}{100 min}log\frac{[10^{20}]}{A_{t}}$

On rearranging,

$\frac{10^{20}}{A_{t}}=31.988$

Or,

$A_{t}=3.13\times 10^{18}$

Therefore, number of molecules unreacted will be $3.13\times 10^{18}$

7 0

3 years ago

Which sphere forms Earth's outermost layer?

svetoff [14.1K]

Answer: I believe the answer is A.

Explanation: Well, the lithosphere is rocks and earth, the hydrosphere makes up all the water on Earth, the biosphere is us, (living things,) and the atmosphere is the air that surrounds us and our planet. So if you go in order, it's basically lithosphere, hydrosphere, biosphere, and then atmosphere.

7 0

2 years ago

An increase in blood CO2 or a decrease in blood ph will lead to which change in respiration?

Galina-37 [17]

Respiratory acidosis

5 0

1 year ago

What is space biology?? <br>

Alex

Answer:

space biology is a fundamental component of space life science. it focuses on smaller organisms such as cell, animals and plants.

4 0

2 years ago