Answer:like my photo bc i like it
Explanation:
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Explanation:
It is known that stronger is the bonding between the atoms of a molecule more difficulty it will face to form vapors. Hence, more heat needs to be provided to the molecule. As a result, it will have high boiling point.
So, in heptanol there is hydrogen bonding. Hence, there is strong bonding so, boiling point of heptanol will be high.
On the other hand, heptane has long carbon chain as compared to pentane. Therefore, heptane will occupy more surface area and thus, more heating will be provided to it. Hence, boiling point of heptane will be greater than the boiling point of pentane.
Thus, we can conclude that rank of given compounds according to start of their boiling point is as follows.
pentane < heptane < heptanol
Answer:
The answer to your question is given below.
Explanation:
1. CH3COOH(aq) + NaHCO3(s) —> CO2(g) + H2O(l) + Na+(aq) + CH3COO-(aq)
The above equation is balanced since the number of atoms of the different elements present on both sides of the equation are equal.
2. CaCl2 + NaHCO3 —> CO2 + CaCO3 + NaCl + H2O
The above equation can be balance as follow:
There are 2 atoms of Cl on the left side and 1 atom on the right side. It can be balance by putting 2 in front of NaCl as shown below:
CaCl2 + NaHCO3 —> CO2 + CaCO3 + 2NaCl + H2O
Now, there are 2 atoms of Na on the right side and 1 atom on the left side. It can be balance by putting 2 in front of NaHCO3 as shown below:
CaCl2 + 2NaHCO3 —> CO2 + CaCO3 + 2NaCl + H2O
Now the equation is balanced.
