All categories

3 years ago

8u^2- 42u^2 Help plzz

Mathematics

2 answers:

zysi [14]3 years ago

7 0

Answer:

- 34u^2

Step-by-step explanation:

8u^2 - 42u^2

= ( 8 - 42 )u^2

= - 34u^2

Snezhnost [94]3 years ago

5 0

$\huge\textsf{Hey there!}$

$\large\textsf{The only thing we can do to solve for this equation is to COMBINE}\\\large\textsf{the LIKE TERMS. }$

$\mathsf{8u^2 - 42u^2}\\\mathsf{= (8u^2- 42u^2)}\\\mathsf{= 8 - 42 \rightarrow \bf -34}\\\textsf{Thus this means }\mathsf{8u^2 - 42u^2}\textsf{ has to equal to }\mathsf{ \bf -34u^2}\\\\\\\\\\\\\boxed{\boxed{\large\textsf{Answer: \bf-34u} \mathsf{\bf ^2}}}\huge\checkmark$

$\large\textsf{Good luck on your assignment and enjoy your day!}\\\\\frak{Amphitrite1040:)}$

You might be interested in

Pls help hurry pls!!!!

EastWind [94]

1 is B.
I’m not sure what 2 is.
3 is A.
4 is B.

8 0

3 years ago

Which table represents the function y = -3x + 2?

Nat2105 [25]

Answer:

first one

Step-by-step explanation:

if you plug the inputs into the equation, you can see that all of the outputs match the ones in the first chart

0 --> 2

1 --> -1

2 --> -4

3 0

3 years ago

Use the given information to find the exact value of the trigonometric function

eimsori [14]

$\begin{gathered} \csc \theta=-\frac{6}{5} \\ \tan \theta>0 \\ \cos \frac{\theta}{2}=\text{?} \end{gathered}$

Half Angle Formula

$\cos \frac{\theta}{2}=\pm\sqrt[\square]{\frac{1+\cos\theta}{2}}$ $\tan \theta>0\text{ and csc}\theta\text{ is negative in the third quadrant}$ $\begin{gathered} \csc \theta=-\frac{6}{5}=\frac{r}{y} \\ x^2+y^2=r^2 \\ x=\pm\sqrt[\square]{r^2-y^2} \\ x=\pm\sqrt[\square]{6^2-(-5)^2} \\ x=\pm\sqrt[\square]{36-25} \\ x=\pm\sqrt[\square]{11} \\ \text{x is negative since the angle is on the 3rd quadrant} \end{gathered}$ $\begin{gathered} \cos \theta=\frac{x}{r}=\frac{-\sqrt[\square]{11}}{6} \\ \cos \frac{\theta}{2}=\pm\sqrt[\square]{\frac{1+\cos\theta}{2}} \\ \cos \frac{\theta}{2}is\text{ also negative in the 3rd quadrant} \\ \cos \frac{\theta}{2}=-\sqrt[\square]{\frac{1+\frac{-\sqrt[\square]{11}}{6}}{2}} \\ \cos \frac{\theta}{2}=-\sqrt[\square]{\frac{\frac{6-\sqrt[\square]{11}}{6}}{2}} \\ \cos \frac{\theta}{2}=-\sqrt[\square]{\frac{6-\sqrt[\square]{11}}{12}} \\ \\ \end{gathered}$

Answer:

$\cos \frac{\theta}{2}=-\sqrt[\square]{\frac{6-\sqrt[\square]{11}}{12}}$

Checking:

$\begin{gathered} \frac{\theta}{2}=\cos ^{-1}(-\sqrt[\square]{\frac{6-\sqrt[\square]{11}}{12}}) \\ \frac{\theta}{2}=118.22^{\circ} \\ \theta=236.44^{\circ}\text{ (3rd quadrant)} \end{gathered}$

Also,

$\csc \theta=\frac{1}{\sin\theta}=\frac{1}{\sin (236.44)}=-\frac{6}{5}\text{ QED}$

The answer is none of the choices

7 0

1 year ago

I need help on this. The portrait studio can buy photographs on canvas. The small canvas photograph print is $20 and the large c

Whitepunk [10]

<h3>Answer:</h3>

6 large prints
12 small prints

<h3>Step-by-step explanation:</h3>

<em>Numerical Reasoning</em>

Consider a set of prints that consists of 2 small prints and one large print (that is, twice as many small prints as large). The value of that set will be ...

... 2×$20 +45 = $85

To have revenue of at least $510, the studio must sell ...

... $510/$85 = 6

sets of prints. That is, the studio needs to sell at least 6 large prints and 12 small ones.

_____

<em>With an equation</em>

Let x represent the number of large prints the studio needs to sell. Then 2x will represent the number of small prints. Total sales will be ...

... 20·2x +45·x ≥ 510

... 85x ≥ 510

... x ≥ 510/85

... x ≥ 6

The studio needs to sell at least 6 large prints and 12 small prints.

8 0

3 years ago

1. algebraic expression

mixer [17]

Answer:

1. algebraic expression: a mathematical expression containing one or more variables

2. coefficient: the constant preceding the variables in a product

3. constant: a numerical value

4. expression: a mathematical phrase that cannot be determined true or false

5. variable: a letter or symbol used to represent an unknown

Step-by-step explanation:

3 0

3 years ago