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Alex
3 years ago
15

2 What is the correct sequence of steps for the preparation of a pure sample of copper(II) sulfate

Chemistry
1 answer:
Lina20 [59]3 years ago
4 0

Answer:

The correct answer is - B. dissolving → evaporation filtration → crystallisation

Explanation:

The method of the preparation of a pure sample of copper(II) sulfate from dilute sulfuric acid and copper II oxide is given as follows:

step 1. Adding dilute sulfuric acid into a beaker. Using bunsen burner heat the beaker.

step 2. Adding the copper (II) oxide into the beaker and give it a little time at a time to the warm dilute sulfuric acid and stir

step 3. Filtering the mixture into an evaporating vessel to remove the excess copper (II) oxide and water from the filtrate.

Step 4. leave the rest filtrate to crystallize.

Copper (II) Oxide  {CuO (s)}  +  Dilute Sulfuric Acid {H2SO4 (aq)}   →  Copper (II) Sulphate {CuSO4 (s)}   +  Water {H2O}

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Given a sample of poly[ethylene-stat-(vinyl acetate)] A.Calculate the mean repeat unit molar mass for a sample of poly[ethylene-
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Answer:

a) The mean repeat unit molar mass for PEVA is 30.72 g/mol

b) degree of polymerization of the copolymer is 1300

Explanation:

Given that;

the wt% of copolymer consist of 12.9 wt% of vinyl acetate and 87.1 wt% Ethylene.

Basis: 100 g of PEVA consist of 12.9 of vinyl acetate and 87.1g of Ethylene.

now we calculate the mole fraction of vinyl acetate Ethylene in the copolymer;

the molecular weights of vinyl acetate and ethylene are 86.09 g/mol and 28.05 g/mol respectively

so

moles of vinyl acetate = wt. of vinyl acetate / molecular weights of vinyl acetate

moles of vinyl acetate = 12.9 g / 86.09 g/mol

moles of vinyl acetate = 0.1498 mol

moles of Ethylene = wt. of Ethylene / molecular weights of Ethylene

moles of Ethylene = 87.1 g / 28.05  d/mol

moles of Ethylene  = 3.1052 mol

Total moles = 0.1498 mol + 3.1052 mol = 3.255 mol

Next we calculate the mole percent;

mole percent of vinyl acetate X_{V} = moles of vinyl acetate / total  moles

X_{V} = (0.1498 mol / 3.255 mol) × 100

X_{V}  = 4.6%

mole percent of Ethylene X_{E} = moles of Ethylene / total  moles

X_{E}  = (3.1052 mol / 3.255 mol) × 100

X_{E}  = 95.397% ≈ 95.4%

we know that, mean repeat unit molar mass for a sample = ∑X_{i}M_{i}

where X_{i} is the fraction ratio and M_{i} is the molecular  weight

so or the PEVA

mean repeat unit molar mass M = ( X_{V}M_{V}) + ( X_{E}M_{E})

so we substitute

M = ( 4.6% × 86.09) + ( 95.4% × 28.05 )

M = 3.96014 + 26.7597

M = 30.72 g/mol

Therefore, The mean repeat unit molar mass for PEVA is 30.72 g/mol

b)

Degree of polymerization

DP_{n} = \frac{M_{n} }{M}

where M_{n} is the number average molecular weight ( 39,870 g/mol )

so we substitute

DP_{n} = 39,870 g/mol / 30.72 g/mol

DP_{n}  = 1297.85 ≈ 1300   { 3 significance figure }

Therefore, degree of polymerization of the copolymer is 1300

5 0
2 years ago
25.4 g of salt was dissolved in distilled water to make 425 mL of solution.
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What is the theoretical yield of this test reaction? Record answer to the nearest whole number.
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Solution : Given,

Mass of

Mass of

Mass of

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Molar mass of  = 24 g/mole

Molar mass of  = 18 g/mole

First we have to calculate the moles of  and .

Moles of  =

Moles of  =

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From the given reaction, we conclude that

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But the actual moles of  = 42 moles

Excess moles of  = 42 - 40 = 2 moles

So,  is the limiting reagent.

Now we have to calculate the mass of .

From the reaction, we conclude that

1 mole of  gives 1 mole of

20 moles of  gives 20 moles of

Mass of  = Moles of  × Molar mass of  

Mass of  = 20 moles × 18 g/mole = 360 g

The experimental yield of  = 325 g

Therefore, the theoretical yield of  = 360 g

Read more on Brainly.com - brainly.com/question/2525928#readmore

7 0
3 years ago
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