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3 years ago

What is a reactant of a chemical reaction?

1 answer:

6 0

The reactant of a chemical reaction is one of the two or more substances in a chemical reaction. This image should help:

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When diagramming an atom, the electron shells ____________ the nucleus must be filled first?

Nonamiya [84]

Concept: According to the basic concept of the electronic configuration of the element, the electron can be filled first in those shell which has least energy or (n +l) value. Here, n is the principal quantum number on shell and l is the azimuthal quantum number.

Since, the first shell has least value of energy in any atom. So, it should be filled first.

Hence, the correct statement can be written as;

When diagramming an atom, the electron shells _nearest to _ the nucleus must be filled first.

4 0

3 years ago

During dehydration synthesis, an enzyme removes a ____________ functional group from the monomers of one organic molecule and a

Reika [66]

Linking monomers together to form a polymer .This chemical reaction also forms water molecules.

<h3>What is Polymerization?</h3>

This is a type of reaction which involves the linking of two or more monomers to form a polymer.

Dehydration reaction forms water molecules as part of the product thereby making it the most appropriate choice.

Read more about Dehydration here brainly.com/question/1301665

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3 0

2 years ago

Deterioration of buildings, bridges, and other structures through the rusting of iron costs millions of dollars a day. The actua

GrogVix [38]

The value of ∆H when 0.250kg of iron rusts is -1.846 × 10³kJ.

The rust forms when 4.85X10³ kJ of heat is released is 888.916 g.

<h3>Chemical reaction:</h3>

4 Fe + 3O2 ------ 2Fe2O3

∆H = -1.65×10³kJ

A) Given,

mass of iron = 0.250kg = 250 g

<h3>Calculation of number of moles</h3>

moles = given mass/ molar mass

= 250/ 55.85 g/mol.

= 4.476 mol

As we know that,

For the rusting of 4 moles of Fe, ∆H = -1.65×10³kJ

For the rusting of 4.476 moles of Fe ∆H required can be calculated as

-1.65×10³kJ × 4.476 mol/ 4mol

∆H required = -1.846 × 10³kJ

Now,

when 2 mol of Fe2O3 formed, ∆H = - 1.65×10³kJ

It can be said that,

-1.65×10³kJ energy released when 2 mol of Fe2O3 formed

So, -4.6 × 10³kJ energy released when 2 mol of Fe2O3 formed

= 2 × -4.6 × 10³kJ / -1.65×10³kJ

= 5.57 mol of Fe2O3 formed

Now,

mass of Fe2O3 formed = 5.57 mol × 159.59 g/mol

= 888.916 g

Thus, we calculated that the rust forms when 4.85X10³ kJ of heat is released is 888.916 g. and the value of ∆H when 0.250kg of iron rusts is -1.846 × 10³kJ.

learn more about ∆H:

brainly.com/question/24170335

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DISCLAIMER:

The given question is incomplete. Below is the complete question

QUESTION:

Deterioration of buildings, bridges, and other structures through the rusting of iron costs millions of dollars a day. The actual process requires water, but a simplified equation is 4Fe(s) + 3O₂(g) → 2Fe₂O₃(s) ΔH = -1.65×10³kJ

a) What is the ∆H when 0.250kg iron rusts.

(b) How much rust forms when 4.85X10³ kJ of heat is released?

7 0

2 years ago

Write a balanced equation for the complete oxidation reaction that occurs when ethane burns in air

damaskus [11]

<h3>Balanced equation : 2C₂H₆ (g) + 7O₂ (g) ⟶ 4CO₂ (g) + 6H₂O (ℓ)</h3><h3>Further explanation</h3>

Alkanes are saturated hydrocarbons that have single bonds in chains

General formula for alkanes :

$\tt \large{\bold{C_nH_{2n+2}}$