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3 years ago

Find the measure of a 2. 45 135 62 = [?]

Mathematics

1 answer:

nasty-shy [4]3 years ago

3 0

Answer:

Step-by-step explanation:

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The sum of the numbers j,k, and m is 115. The ratio of j to k is 2:7 and the ratio of k to m is 14:5. What is the value of k?

I am Lyosha [343]

Answer:

I know how to help you.

Step-by-step explanation:

There is a web site called Khan Academy and it can help you understand how to solve it and it is completely free and you can use it as much as you want. There are videos that explain it to you and problems like help with practice I 100% reccomend it!

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3 years ago

Read 2 more answers

PLEASE HELP ME ( MULTIPLE CHOICE)!!

Anton [14]

Answer:

Step-by-step explanation:

an undefined slope has the same x value no matter what y value it has, therefore, D

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4 0

3 years ago

At a bargain store, Tanya bought 4 items that each cost the same amount. Tony bought 5 items that each cost the same amount, but

Alex_Xolod [135]

If x is the amount that Tanya paid for each item, then Tony's items would be x-2.25. So:

3x=4(x-2.25)

3x=4x-9

x=9

x-2.25=6.75

Tanya spent $9 on each item; Tony spent $6.75 on each of his items. ☺☺☺☺

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3 years ago

Please help ASAP!!<br><br><br> Will Mark Brainiest

mr Goodwill [35]

I am pretty sure its JT

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3 years ago

Calculus 3 chapter 16

o-na [289]

Evaluate $\vec F$ at $\vec r$ :

$\vec F(x,y,z) = x\,\vec\imath + y\,\vec\jmath + xy\,\vec k \\\\ \implies \vec F(\vec r(t)) = \vec F(\cos(t), \sin(t), t) = \cos(t)\,\vec\imath + \sin(t)\,\vec\jmath + \sin(t)\cos(t)\,\vec k$

Compute the line element $d\vec r$ :

$d\vec r = \dfrac{d\vec r}{dt} dt = \left(-\sin(t)\,\vec\imath+\cos(t)\,\vec\jmath+\vec k\bigg) \, dt$

Simplifying the integrand, we have

$\vec F\cdot d\vec r = \bigg(-\cos(t)\sin(t) + \sin(t)\cos(t) + \sin(t)\cos(t)\bigg) \, dt \\ ~~~~~~~~= \sin(t)\cos(t) \, dt \\\\ ~~~~~~~~= \dfrac12 \sin(2t) \, dt$

Then the line integral evaluates to

$\displaystyle \int_C \vec F\cdot d\vec r = \int_0^\pi \frac12\sin(2t)\,dt \\\\ ~~~~~~~~ = -\frac14\cos(2t) \bigg|_{t=0}^{t=\pi} \\\\ ~~~~~~~~ = -\frac14(\cos(2\pi)-\cos(0)) = \boxed{0}$

3 0

1 year ago