Answer:
4th Option
Explanation:
HNO3 is an acid, KOH is a base and they react to produce KNO3 which is a salt and H2O water.
So this reaction is a neutralisation reaction.
A Bose-Einstein condensate is a group of atoms cooled to within a hair of absolute zero. When they reach that temperature the atoms are hardly moving relative to each other; they have almost no free energy to do so. At that point, the atoms begin to clump together, and enter the same energy states.
Answer:
38.4 atm
Explanation:
Data obtained from the question include:
V1 (initial volume) = 3200 L
P1 (initial pressure) = 3.00 atm
V2 (final volume) = 250.0 L
P2 (final pressure) = ?
Using Boyle's law equation P1V1 = P2V2, the final pressure can be obtained as follow:
P1V1 = P2V2
3 x 3200 = P2 x 250
Divide both side by 250
P2 = 3 x 3200/250
P2 = 38.4 atm
Therefore, the pressure of the gas if ethylene is supplied by a 250.0 L tank is 38.4 atm
-1 charge = the atom has gained one electron
9+1=10
Answer:
The new pressure will be 1.86 atm.
Explanation:
As the volume increases, the gas particles (atoms or molecules) take longer to reach the walls of the container and therefore collide less times per unit time against them. This means that the pressure will be less because it represents the frequency of gas strikes against the walls. In this way pressure and volume are related, determining Boyle's law.
Boyle's law says that at constant temperature, the volume of a fixed mass of gas is inversely proportional to the pressure it exerts:
P*V=k
To determine the change in pressure or pressure during a transformation to constant pressure, the following expression is applied:
P1*V1=P2*V2
In this case:
- P1= 0.62 atm
- V1= 3 L
- P2= ?
- V2= 1 L
Replacing:
0.62 atm* 3L= P2* 1 L
Solving:

P2= 1.86 atm
<u><em>The new pressure will be 1.86 atm.</em></u>