Answer:
570 N
Explanation:
Draw a free body diagram on the rider. There are three forces: tension force 15° below the horizontal, drag force 30° above the horizontal, and weight downwards.
The rider is moving at constant speed, so acceleration is 0.
Sum of the forces in the x direction:
∑F = ma
F cos 30° - T cos 15° = 0
F = T cos 15° / cos 30°
Sum of the forces in the y direction:
∑F = ma
F sin 30° - W - T sin 15° = 0
W = F sin 30° - T sin 15°
Substituting:
W = (T cos 15° / cos 30°) sin 30° - T sin 15°
W = T cos 15° tan 30° - T sin 15°
W = T (cos 15° tan 30° - sin 15°)
Given T = 1900 N:
W = 1900 (cos 15° tan 30° - sin 15°)
W = 570 N
The rider weighs 570 N (which is about the same as 130 lb).
300/8 = 37.5
37.5 x 12 = 450
New temp. = 450 K
Hope this helps!
Answer:
Part(a): The frequency is 
.
Part(b): The speed of the wave is 
.
Explanation:
Given:
The distance between the crests of the wave, 
.
The time required for the wave to laps against the pier, 
The distance between any two crests of a wave is known as the wavelength of the wave. So the wavelength of the wave is 
.
Also, the time required for the wave for each laps is the time period of oscillation and it is given by 
.
Part(a):
The relation between the frequency and time period is given by
Substituting the value of 
in equation (1), we have
Part(b):
The relation between the velocity of a wave to its frequency is given by
Substituting the value of 
and 
in equation (2), we have
Potential energy because it has enough energy to do work but non has been done yet.
Answer:
<h3>The answer is 0.54 m</h3>
Explanation:
The wavelength of a wave can be found by using the formula
where
c is the velocity
f is the frequency
So we have
We have the final answer as
<h3>0.54 m</h3>
Hope this helps you
