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dimulka [17.4K]
3 years ago
11

An equation that shows only the chemical formulas without

Chemistry
1 answer:
Ivahew [28]3 years ago
7 0

Answer: skeleton equation

Explanation:

You might be interested in
g A 500. mL solution contains 0.665 M NaC2H3O2 and 0.475 M HC2H3O2. What mass of HCl in grams needs to be added for the solution
77julia77 [94]

Answer:

7.38g HCl

Explanation:

Using H-H equation for acetic buffer:

pH = pKa + log [NaC2H3O2] / [HC2H3O2]

<em>Where pKa is -log Ka = 4.74 and [] could be taken as moles of each compound.</em>

The initial moles of each specie is:

[NaC2H3O2]:

0.500L * (0.665mol/L) = 0.3325moles

[HC2H3O2]:

0.500L * (0.475mol/L) = 0.2375 moles

That means total moles are:

[NaC2H3O2] + [HC2H3O2] = 0.57 moles <em>(1)</em>

And solving H-H equation for a pH of 4.21:

4.21 = 4.74 + log [NaC2H3O2] / [HC2H3O2]

0.29512 = [NaC2H3O2] / [HC2H3O2] <em>(2)</em>

Replacing (1) in (2):

0.29512 = 0.57mol - [HC2H3O2] / [HC2H3O2]

0.29512 [HC2H3O2] = 0.57mol - [HC2H3O2]

1.29512 [HC2H3O2] = 0.57mol

[HC2H3O2] = 0.44 moles

The HCl reacts with NaC2H3O2 producing HC2H3O2, that means you need to add:

0.44 moles - 0.2375 moles =

0.2025 moles of HCl

Using molar mass of HCl (36.45g/mol), to convert these moles to grams:

0.2025 moles * (36.45g/mol) =

<h3>7.38g HCl</h3>

8 0
3 years ago
How much energy is needed to melt 25.4 grams of I2?
Vilka [71]
We know the equation of latent heat:

Q = mL

(Energy = mass * latent heat)

Therefore, this problem is a regular application of this:

Q = 25.4 * 61.7

Q = 1567,18

With the 3 digits:

Q = 1570 J
4 0
3 years ago
Read 2 more answers
Which of the following best describes the Earth's movement around the sun?
dimaraw [331]

Answer:

D)The Earth moves in an elliptical orbit around the sun

7 0
4 years ago
How many moles are in 98.3 grams of aluminum hydroxide, Al(OH)3?
Musya8 [376]
We have to calculate the molar mass of  AL(OH)₃
Atomic mass (Al)=27 amu
Atomic mass (O)=16 amu
Atomic mass (H)=1 amu

molecular weight= 27 amu+3(16 amu + 1 amu) =78 amu.

Therefore, the molar mass of Al (OH)₃ is 78 g/ mol

Now, we calculate the number of moles in 98.3 g of aluminum hydroxide.

78 g-------------------1 mol
98.3 g-----------------  x

x=(98.3 g * 1 mol) / 78 g=1.26 moles.

Answer: 1.26 moles.
6 0
3 years ago
in the following reaction 10.5 moles of chromium are added to 6.8 moles of oxygen find limiting an excess reactants and answer t
drek231 [11]

Answer:

If 3.4 moles of carbon dioxide (CO2) form at the end of the reaction, 1.7 moles of oxygen gas

(02) and 3.4 moles of carbon monoxide (CO) entered the reaction

Explanation:

The rule of three or is a way of solving problems of proportionality between three known

values and an unknown value, establishing a relationship of proportionality between all of

them. That is, what is intended with it is to find the fourth term of a proportion knowing the

other three. Remember that proportionality is a constant relationship or ratio between different

magnitudes.

If the relationship between the magnitudes is direct, that is, when one magnitude increases, so

does the other (or when one magnitude decreases, so does the other), the direct rule of three

must be applied. To solve a direct rule of three, the following formula must be followed:

ab

cx

So

C*b

T =

a

In this case, it is possible to use the reaction stoichiometry of the reaction (that is, the

relationship between the amount of reagents and products in a chemical reaction) and the rule

of three to calculate the quantities of moles requested:

.

,

If by stoichiometry 2 moles of CO2 are formed by 1 mol of O2, if 3.4 moles of CO2 are

formed, how many moles of O2 are needed?

molesofo2 = 3.42

=

moles of O2=1.7 moles

• If by stoichiometry 2 moles of CO2 are formed by 2 moles of CO, if 3.4 moles of CO2 are

formed, how many moles of CO are needed?

molesof CO =

=

3.4*2

2

moles of CO=3.4

8 0
2 years ago
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