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aksik [14]
3 years ago
5

12. Calculate the hydroxide ion concentration of a solution with pH = 10.25. Show all calculations leading to an answer.

Chemistry
2 answers:
Alex787 [66]3 years ago
6 0
PH= log[H3O+]
10.25=log [H3O+]
[H3O+] = 10^10.25
[H3O+]= 1.778 ×10^10
kkurt [141]3 years ago
6 0
<span>pH + pOH = 14 10.25 + pOH = 14 pOH = 14 - 10.25 = 3.75 Now, knowing the pOH we can find the OH^- since pOH is -log [OH-] [OH-] = 10^-3.75 = 1.78x10^-4 M</span>
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How many grams of the excess reactant remain assuming the reaction goes to completion and that you start with 15.5g of na2s and
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5 0
2 years ago
A gas mixture of Ne and Ar has a total pressure of 4.00 atm and contains 16.0 mol of gas. If the partial pressure of Ne is 2.75
Stolb23 [73]

Answer:

5 moles of Argon is present in the mixture.

Explanation:

Total pressure of the gaseous mixture = 4 atm

Total number of moles = 16

Partial pressure of Ne = 2.75 atm

By Dalton's law of partial pressure, the total pressure of gaseous mixture is the sum of partial pressures of individual gases which are non-reactive.

Hence:

P_{total}=P_{Ar}+P_{Ne}\\4=P_{Ar}+2.75\\P_{Ar}=1.25\ atm

Also :

Partial pressure = mole fraction*total pressure

P_{Ar}=X_{Ar}P_{total}

X_{Ar}=\frac{1.25}{4}=0.3125

\frac{n_{Ar}}{n_{total}}=0.3125\\n_{Ar}=5

∴Number of moles of Argon = 5

4 0
3 years ago
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