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pochemuha
3 years ago
7

A given sample of gas has a volume of 5.20 L at 60.°C and 1.00 atm pressure. Calculate its pressure if the volume is changed to

6.00 L and the temperature to 27°C (assume the amount of gas does not change)
Chemistry
1 answer:
BigorU [14]3 years ago
5 0

Answer:

0.78 atm

Explanation:

Applying general gas equation

PV/T= P'V'/T'................ Equation 1

Where P = initial pressure, T = Initial temperature, V = Initial Volume, P' = Final pressure, V' = Final Volume, T' = Final Temperature.

make P' the subject of the equation

P' = PVT'/TV'.............. Equation 2

From the question,

Given: P = 1.00 atm, V = 5.20 L, T = 60°C = (273+60) = 333K, V' = 6.00 L, T' = 27°C = (27+273)K = 300 K

Substitute these values into equation 2

P' = (1×5.2×300)/(333×6)

P' = 1560/1998

P' = 0.78 atm.

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3 years ago
What is the half life of the graphed material?
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A 17.11 gram sample of an organic compound containing only C, H, and O is analyzed by combustion analysis and 21.71 g CO2 and 5.
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Answer:  The empirical formula and the molecular formula of the organic compound is CHO and C_4H_4O_4 respectively.

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For calculating the mass of hydrogen:

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Moles of C =\frac{\text{ given mass of C}}{\text{ molar mass of C}}= \frac{5.921g}{12g/mole}=0.493moles

Moles of H=\frac{\text{ given mass of H}}{\text{ molar mass of H}}= \frac{0.658g}{1g/mole}=0.658moles

Mass of O=\frac{\text{ given mass of O}}{\text{ molar mass of O}}= \frac{10.53g}{16g/mole}=0.658moles

Step 2 : For the mole ratio, divide each value of moles by the smallest number of moles calculated.

For C =\frac{0.493}{0.493}=1

For H =\frac{0.658}{0.493}=1

For O=\frac{0.658}{0.493}=1

The ratio of C : H: O =  1: 1: 1

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n=\frac{\text {Molecular mass}}{\text {Equivalent mass}}=\frac{104.1}{29}=4

Thus molecular formula = n\times {\text {Empirical formula}}=4\times CHO=C_4H_4O_4

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