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pochemuha
3 years ago
7

A given sample of gas has a volume of 5.20 L at 60.°C and 1.00 atm pressure. Calculate its pressure if the volume is changed to

6.00 L and the temperature to 27°C (assume the amount of gas does not change)
Chemistry
1 answer:
BigorU [14]3 years ago
5 0

Answer:

0.78 atm

Explanation:

Applying general gas equation

PV/T= P'V'/T'................ Equation 1

Where P = initial pressure, T = Initial temperature, V = Initial Volume, P' = Final pressure, V' = Final Volume, T' = Final Temperature.

make P' the subject of the equation

P' = PVT'/TV'.............. Equation 2

From the question,

Given: P = 1.00 atm, V = 5.20 L, T = 60°C = (273+60) = 333K, V' = 6.00 L, T' = 27°C = (27+273)K = 300 K

Substitute these values into equation 2

P' = (1×5.2×300)/(333×6)

P' = 1560/1998

P' = 0.78 atm.

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Which type of fat is a solid at room temperature and does not have double bonds between carbon
melamori03 [73]

Answer:

Saturated Fats

Explanation:

Saturated fats are all of the above.

Also, Saturated fat is very unhealthy. Only consume it in small amounts.

7 0
3 years ago
Read 2 more answers
2 HI(g) ⇄ H2(g) + I2(g) Kc = 0.0156 at 400ºC 0.550 moles of HI are placed in a 2.00 L container and the system is allowed to rea
Alex_Xolod [135]

<u>Answer:</u> The concentration of hydrogen gas at equilibrium is 0.0275 M

<u>Explanation:</u>

Molarity is calculated by using the equation:

\text{Molarity}=\frac{\text{Number of moles}}{\text{Volume of solution (in L)}}

Moles of HI = 0.550 moles

Volume of container = 2.00 L

\text{Initial concentration of HI}=\frac{0.550}{2}=0.275M

For the given chemical equation:

                          2HI(g)\rightleftharpoons H_2(g)+I_2(g)

<u>Initial:</u>                  0.275

<u>At eqllm:</u>           0.275-2x      x         x

The expression of K_c for above equation follows:

K_c=\frac{[H_2][I_2]}{[HI]^2}

We are given:

K_c=0.0156

Putting values in above expression, we get:

0.0156=\frac{x\times x}{(0.275-2x)^2}\\\\x=-0.0458,0.0275

Neglecting the negative value of 'x' because concentration cannot be negative

So, equilibrium concentration of hydrogen gas = x = 0.0275 M

Hence, the concentration of hydrogen gas at equilibrium is 0.0275 M

4 0
3 years ago
3Al + 3NH4ClO4 → Al2O3 + AlCl3 + 3NO + 6H2O<br> How many moles of AlCl3 are produced?
zhuklara [117]

Answer: 1 mol of AlCl_3 will be produced from this reaction.

Explanation: Reaction follows,

3Al+3NH_4ClO_4\rightarrow Al_2O_3+AlCl_3+3NO+6H_2Oc

As seen from the balanced chemical equation above, we get

For every 3 moles of Aluminium and 3 moles of NH_4ClO_4, 1 mole of Al_2O_3 is formed.

For every 3 moles of Aluminium and 3 moles of NH_4ClO_4, 1 mole of AlCl_3 is formed.

For every 3 moles of Aluminium and 3 moles of NH_4ClO_4, 3 moles of NO is formed.

For every 3 moles of Aluminium and 3 moles of NH_4ClO_4, 6 moles of H_2O is formed.

7 0
4 years ago
Read 3 more answers
A) An iron nail is attracted to a magnet.
11111nata11111 [884]

there's no question on here

4 0
3 years ago
Read 2 more answers
Is this right, I feel like its wrong
hjlf

It is correct, next time re-check your answer and don't second guess yourself. ;3

7 0
3 years ago
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