Answer:
a) fem = 5.709 V, b) t = 0.196 s, c) t = 0.589 s, d) T = 0.785 s
Explanation:
This is an exercise in Faraday's law
fem= - N 
fem = - N 
The magnetic field and the area are constant
fem = - N B A 
fem = - N B A (-sin θ) 
fem = N B (π d² / 4) sin θ w
fem= 
N B d² w sin θ
with this expression we can correspond the questions
a) the peak of the electromotive force
this hen the sine of the angle is 1
sin θ = 1
fem = 77 1.18 0.10² 8.0
fem = 5.709 V
b) as the system has a constant angular velocity, we can use the angular kinematics relations
θ = w₀ t
t = θ/w₀
Recall that the angles are in radians, so the angle for the maximum of the sine is
θ= π/2
t = 
t = 0.196 s
c) for the electromotive force to be negative, the sine function of being
sin θ= -1
whereby
θ = 3π/ 2
t = 
t = 0.589 s
d) This electromotive force has values that change sinusoidally with an angular velocity of
w = 8 rad / s
angular velocity and period are related
w = 2π / T
T = 2π / w
T = 2π / 8
T = 0.785 s
Answer:
RE of Hydrogen = 6.47 x RE of Krypton
Explanation:
Actually the correct formula for comparing rate of effusion (RE) of two gases is:
RE of Gas A
------------------- = √ ( Molar mass of B / Molar mass of A)
RE of Gas B
You can designate which of the two gases you have (hydrogen and krypton) will be your gas A and gas B. So for this particular problem, let us make hydrogen as gas A and Krypton as gas B. So the equation becomes:
RE of Hydrogen
------------------------- = √ (Molar mass of Krypton / Molar mass of Hydrogen)
RE of Krypton
Get the molar masses of Hydrogen and Krypton in the periodi table:
RE of Hydrogen
------------------------- = √ (83.798 g/mol / 2 g/mol)
RE of Krypton
RE of Hydrogen
------------------------- = 6.47 ====> this can also be written as:
RE of Krypton
RE of Hydrogen = 6.47 x RE of Krypton
It means that the rate of effusion of Hydrogen gas will be 6.47 faster than the rate of effusion of Krypton gas. With the type of question you have, it doesn't matter which gases goes on your numerator and denominator. What's important is that you show the rate of effusion of a gas with respect to the other. But if that's concerns you the most, then take the gas which was stated first as your gas A and the latter as your gas B unless the problem tells you which one will be on top and which is in the bottom.
The student's answer is wrong because the unit of his answer is meter - seconds which is not unit of distance (meter).
<h3>
Total distance traveled by an object</h3>
The total distance traveled by an object projected upward is calculated from third equation of motion a shown below.
<h3>Equation for the motion of the object</h3>
v² = u² - 2gh
where;
- v is final velocity
- u is initial velocity
- g is acceleration due to gravity
at maximum height, the final velocity is zero, v = 0
0 = u² - 2gh
2gh = u²
h = u²/2g
The equation for the total distance an object has traveled during upward projection is "h = u²/2g".
<h3>Dimension of the student's answer;</h3>
d = (2vh)/g = (m/s x m) / (m/s²) = (m²/s) / (m/s²) = m.s
Thus, the student's answer is wrong because the unit of his answer is meter - seconds which is not unit of distance (meter).
Learn more about distance here: brainly.com/question/2854969
#SPJ1
the ratio of the force produced by a machine to the force applied to it, used in assessing the performance of a machine.
Here, you need to apply second equation of Kinematics
S = ut + 1/2 at²
s = at²/2 [ As initial velocity (u) = 0 ]
Now, a = 9.8 m/s²
t = 2.7 s
Substitute their values in the formula:
s = 9.8 × (2.7)² / 2
s = 35.721 m
After rounding-off to the nearest hundredth value, it would be 36 m
Finally, your answer would be option B.
Hope this helps!
