The ph after 17.0 ml of 0.15 m Koh has been added to 15 ml of 0.20 m hclo4 is <u>3.347</u>.
Titration is a commonplace laboratory technique of quantitative chemical analysis to determine the attention of an identified analyte. A reagent, termed the titrant or titrator, is ready as a trendy answer of recognized awareness and extent.
<u>Calculation:-</u>
Normality of acid Normality of base
= nMV nMV
= 1 × 0. 15 × 0.017 1 × 0. 20 ×0.015 L
= 2.55 × 10⁻³ = 3 × 10⁻³
The overall base will be high
net concentration = 3× 10⁻³ - 2.55 × 10⁻³
= 0.45 × 10⁻³
= 4.5× 10⁻⁴
pH = -log[4.5 × 10⁻⁴]
= 4 - log4.4
= <u>3.347</u>
A titration is defined as 'the manner of determining the amount of a substance A by using adding measured increments of substance B, the titrant, with which it reacts till precise chemical equivalence is completed the equivalence factor.
Learn more about titration here:-brainly.com/question/186765
#SPJ4
A indicator is a weak organic acid or a base which has shows different colors in acidic and basic mediums. The color change occurs when the weak acidic or basic indicator dissociates to give its respective conjugate base or conjugate acid.
Therefore the correct option would be Indicators are weak acids or bases.
The products and reactants weigh the same since u have to balance out the equation to have an equal number of molecules on bothsides
<span>To find: Sample error in percent
Solution:
Formula:
((Experimental value-theoretical value)/theoretical value)*100
where, theoretical value = 100°c
and, experimental value = 102°c (sample 1) 99.2°c (sample 2)
Sample error (in percentage) when boiling level was 102°c = ((102°c-100°c)/100°c)*100 = 2%
Sample error (in percentage) when boiling level was 99.2°c = ((99.2°c-100°c)/100°c)*100 = -0.8%</span>
Answer:
Oxygen and Carbon dioxide
Explanation:
Oxygen is required for respiration whereby energy is released from natural occurring nutrients accompanied by the release of water and carbon dioxide. carbon dioxideis also required by plants to photosynthesise.
Oxygen and carbon dioxide in the troposphere supports life as by enabling respiration in organisms and photosynthesise in plants can. Without oxygen in an environment, only life forms that live by anaerobic respiration will thrive. This affects a regions carrying capacity
