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Artyom0805 [142]
3 years ago
9

Is NaHCO3 a binary compound​

Chemistry
1 answer:
gladu [14]3 years ago
3 0

Answer:

No

Explanation:

Binary compounds contain only 2 distinct elements.

For example magnesium oxide MgO is a binary compound.

NaHCO3 contains 4 distinct elements.

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____________ limits or stops the growth of bacteria.
Kaylis [27]

Answer:

Vaccines

Explanation:

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3 years ago
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What is the chemical reaction of aluminum and ferric oxide to produce iron and aluminum oxide?
AnnZ [28]

Answer:

Ferric oxide reacts with aluminium to produce aluminium oxide and iron. The balanced chemical equation for the given reaction is : Fe2O3 + 2Al → Al2O3 + 2Fe.

6 0
3 years ago
Calculate the missing variables in each experiment below using Avogadro’s law.
blagie [28]

Answer:

The answer to your question is: letter c

Explanation:

Data

V1 = 612 ml    n1 = 9.11 mol

V2 = 123 ml    n2 = ?

Formula

                               \frac{V1}{n1}  =  \frac{V2}{n2}

                                         n2 = \frac{n1V2}{V1}

                                         n2 = \frac{(9.11)((123)}{(612)}

                                                n2 = 1.83 mol                                                

5 0
3 years ago
The component that dissolves the other component is called the
zheka24 [161]

Answer:

The component that dissolves the other component is called the solvent. Solute – The component that is dissolved in the solvent is called solute

6 0
3 years ago
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How many moles of S would I have if I had 11 grams? (Stoichiometry) HELP
zepelin [54]
<h3>Answer:</h3>

0.34 mol S

<h3>General Formulas and Concepts:</h3>

<u>Math</u>

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right<u> </u>

<u>Chemistry</u>

<u>Atomic Structure</u>

  • Reading a Periodic Table

<u>Stoichiometry</u>

  • Using Dimensional Analysis
<h3>Explanation:</h3>

<u>Step 1: Define</u>

11 g S

<u>Step 2: Identify Conversions</u>

[PT] Molar Mass of S - 32.07 g/mol

<u>Step 3: Convert</u>

  1. Set up:                                \displaystyle 11 \ g \ S(\frac{1 \ mol \ S}{32.07 \ g \ S})
  2. Multiply/Divide:                  \displaystyle 0.343 \ mol \ S

<u>Step 4: Check</u>

<em>Follow sig fig rules and round. We are given 2 sig figs.</em>

0.343 mol S ≈ 0.34 mol S

4 0
3 years ago
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