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Artyom0805 [142]
3 years ago
9

Is NaHCO3 a binary compound​

Chemistry
1 answer:
gladu [14]3 years ago
3 0

Answer:

No

Explanation:

Binary compounds contain only 2 distinct elements.

For example magnesium oxide MgO is a binary compound.

NaHCO3 contains 4 distinct elements.

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Carly lives in an area with temperatures that are always very warm. Carly also lives in an area that is close to the equator. Wh
mariarad [96]

The answer would be B.

hope this helps,

Trey

3 0
3 years ago
What are the units of k in the following rate law?
Ludmilka [50]

Answer:

B. \frac{1}{M^{2} s }

Explanation:

The unit for rate is M/s while the unit for each molecule should be M. You can find the unit for k by putting the units for rate and the molecules into the equation

rate= k{X][Y]

M/s= k * M^{2} * M^{1}

k= (M/s) / (M^{3})

k= \frac{1}{M^{2} s }

You can also use this predetermined formula to solve this problem faster: k= \frac{M^{1-n} }{s }

Where n is the number of molecule. There are 3 molecule(2X and 1Y) so n=3, so

k= \frac{M^{1-n} }{s }

k= \frac{M^{1-3} }{s }= \frac{m^{-2}}{s}= \frac{1}{M^{2} s }

8 0
4 years ago
What do we need to learn about inclined planes
Troyanec [42]

Answer: Inclined plane, simple machine consisting of a sloping surface, used for raising heavy bodies. The force required to move an object up the incline is less than the weight being raised, discounting friction. The steeper the slope, or incline, the more nearly the required force approaches the actual weight.

Explanation:

4 0
3 years ago
Which atom would be expected to have a half-filled 6s subshell
eduard

Answer: I think the answer is Cesium (Cs)

Explanation:

A half-filled 6s subshell would be 6s^1

4 0
3 years ago
Which types of electron orbitals will have higher energy than a 4d orbital?
alexdok [17]

Answer:

D) 4f

Explanation:

To determine which electron orbital that will have higher energy than a 4d orbital, we write the electron configuration starting with s-orbital.

1s

2s         2p

3s         3p          3d       3f

4s         4p          4d       4f

5s         5p           5d       5f

6s         6p          6d       6f

7s         7p           7d       7f

In ascending order, 1s, 2s, 2p, 3s, 3p, 4s, 3d, 4p, 5s, 3f, <u>4d</u><em>,</em> 5p, 6s, 4f, 5d, 6p, 7s, 5f, 6d, 7p, 6f, 7d, 7f.

From the electronic configuration formula above, the electron orbitals that have higher energy than a 4d orbital are 5p, 6s, 4f, 5d, 6p, 7s, 5f, 6d, 7p, 6f, 7d, 7f.

Therefore, 4f is the correct answer.

8 0
3 years ago
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