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swat32
3 years ago
8

50 POINTS BRAINLIEST - How many L of gas would 200.0 grams of CCl^4 occupy at STP? pls show work

Chemistry
1 answer:
Paladinen [302]3 years ago
8 0

Answer:Oxygen has a molar mass of 16.00 g/mol. One mole of CO2 contains 32.00 grams of oxygen. One mole equals 22.4L at standard temperature and pressure. 0.60L CO2 equals 0.0268 mol at STP.

Explanation:

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Explanation:

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3 years ago
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What is the name of KMnO3???
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The answer is potassium magnate
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C. identify a set of four possible quantum numbers for the circled electron in manganese (mn). (there is more than one correct a
steposvetlana [31]
Although you have not provided the circled electron, I can help you with a wide explanation.

1) Atomic number of manganese is 25. That means that it has 25 protons and 25 electrons.

2) Those 25 electrons are distributed (electron configuration) as per the quantum rules:

1s² 2s² 2p⁶ 3s² 3p⁶ 4s² 3d⁵

3) The most reasonable is that you have been asked to give the possible quantum numbers for an electron in the 4s or 3d.

4) Those are 7 electrons and these are their possible sets of quantum numbers:
i) For the two electrons in 4s: 
n is the main energy level so n = 4
l tells the kind of orbital, which is s, so l = 0
ml is also 0 (it can be from -l to + l, so given that l i s0, ml is 0)
ms: one is +/12 and the other is -1/2 (this is the spin number).


ii) For the 5 electrons in 3d

n = 3
l can be 0, 1, or 2
if l = 0, then ml = 0

if l = 1, then ml can be -1, 0 , or 1 (from - l to + l)


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5 0
3 years ago
What are minerals in the rest of the water.
garri49 [273]

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5 0
3 years ago
A solution was found to have a 15.6 % transmittance at 500 nm, its wavelength of maximum absorption, using a cell with a path le
Gnesinka [82]

For the absorbance of the solution in a 1.00 cm cell at 500 nm  is mathematically given as

A’ = 0.16138

<h3>What is the absorbance of the solution in a 1.00 cm cell at 500 nm?</h3>

Absorbance (A) 2 – log (%T) = 2 – log (15.6) = 0.8069

Generally, the equation for the Beer’s law is mathematically given as

A = ε*c*l

0.8069 = ε*c*(5.00 )

ε*c = 0.16138 cm-1

then for when ε*c is constant

l’ = 1.00

A’ = (0.16138 cm-1)*(1.00 cm)

A’ = 0.16138

In conclusion, the absorbance of the solution in a 1.00 cm cell at 500 nm is

A’ = 0.16138

Read more about Wavelength

brainly.com/question/3004869

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