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Igoryamba
3 years ago
7

Lee is in customer service. How can she best support her internal customer, Dan? O al Prioritize other tasks and customers O b)

Ask him a lot of personal questions O c) Give him her full attention when he's speaking O d) Check with him before completing basic tasks
Engineering
1 answer:
frozen [14]3 years ago
7 0

Answer:

freeeeeeeeeeeeeeeeeeeeeeeee

Explanation:

VVVVVVVVVVVVVVVVVVVVV

You might be interested in
Which measure is a correct definition of density?
Gnom [1K]

Answer:

Density is commonly expressed in units of grams per cubic centimetre.

Explanation:

4 0
2 years ago
A refrigerator removes heat from a refrigerated space at 0°C at a rate of 2.2 kJ/s and rejects it to an environment at 20°C. wha
Anika [276]

Answer:

The minimum power required by the refrigerator is 161 W to remove heat from a refrigerated space.

<u>Explanation:</u>

To calculate the power required to refrigerate we know that COP of refrigerator is represented as C O P=\frac{Q_{\text {coid}}}{W}C O P=\frac{T_{\text {cold }}}{T_{\text {hot }}-T_{\text {cold}}}. Given that, T_{\text {cold}}=0^{\circ} \mathrm{C}, T_{\text {hot}}=22^{\circ} \mathrm{C} \text { and } Q_{\text {cold}}=2.2 \mathrm{KJ} / \mathrm{s}

O P=\frac{T_{\text {cold }}}{T_{\text {hot }}-T_{\text {cold }}}=\frac{0+273}{(22+273)-(0+273)}=\frac{273}{293-273}=\frac{273}{20}=13.65

C O P=\frac{Q_{\text {cold}}}{w}=>13.65=\frac{2.2}{w} W=\frac{2.2}{13.65}=0.161 \mathrm{KJ} / \mathrm{s}=161 \mathrm{W}(0.1 \mathrm{KJ} / \mathrm{s}=100 \mathrm{W})

Thus we can say that <em>minimum power required by refrigerator if a refrigerator removes heat to an environment at 20°C from a refrigerated space at 0°C at 2.2 kJ/s is 161W.</em>

5 0
3 years ago
Pleaseeeeeeeeeeeeee answer
Lapatulllka [165]
Answer 25/2

100/8 = 25/2
4 0
3 years ago
Read 2 more answers
. In the U.S. fuel efficiency of cars is specified in miles per gallon (mpg). In Europe it is often expressed in liters per 100
ki77a [65]

Answer:

MATLAB Code is written below with comments in bold, starting with % sign.

MATLAB Code:

function L = Lkm(mpg)

 L = mpg*1.60934/3.78541;  %Conversion from miles per gallon to km per   liter

 L = L^(-1);  %Conversion to liter per km

 L = L*100;   %Conversion to liter per 100 km

end

Explanation:

A function named Lkm is defined with an output variable "L" and input argument "mpg". So, in argument section, we give function the value in miles per gallon, which is stored in mpg. Then it converts it into km per liter by following formula:

L = (mpg)(1.60934 km/1 mi)(1 gallon/3.78541 liter)

Then this value is inverted to convert it into liter per km, in the next line. Then to find out liter per 100 km, the value is multiplied by 100 and stored in variable "L"

Test Run:

>> Lkm(100)

ans =

   2.3522

6 0
3 years ago
Pascal's law tells us that a. force per unit area is constant within a closed container completely filled with a fluid if measur
Elis [28]

Answer:

d). a and c

Explanation:

According to Pascal's law, when force is applied to a fluid, the pressure will increase equally in all direction of the container. Pascal law says that the pressure is transmitted undiminised in all direction inside a closed container. And the pressure inside the closed container is constant when measured at the same height above the datum.

Hence option d is correct.

4 0
4 years ago
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