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4 years ago

Why will screws never replace nails

Engineering

1 answer:

cupoosta [38]4 years ago

3 0

Answer:

because people have different opinions on nails and screws

Explanation:

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BCC lithium has a lattice parameter of 3.5089 3 10–8 cm and contains one vacancy per 200 unit cells. Calculate (a) the number of

Tanya [424]

(a) The number of vacancies per cubic centimeter is 1.157 X 10²⁰

(b) ρ = n X (AM) / v X Nₐ

<u>Explanation:</u>

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Given-

Lattice parameter of Li = 3.5089 X 10⁻⁸ cm

1 vacancy per 200 unit cells

Vacancy per cell = 1/200

(a)

Number of vacancies per cubic cm = ?

Vacancies/cm³ = vacancy per cell / (lattice parameter)³

Vacancies/cm³ = 1 / 200 X (3.5089 X 10⁻⁸cm)³

Vacancies/cm³ = 1.157 X 10²⁰

Therefore, the number of vacancies per cubic centimeter is 1.157 X 10²⁰

(b)

Density is represented by ρ

ρ = n X (AM) / v X Nₐ

where,

Nₐ = Avogadro number

AM = atomic mass

n = number of atoms

v = volume of unit cell

4 0

4 years ago

For goods-producing firms, at which of the following levels of resource planning does scheduling for individual subassemblies an

VashaNatasha [74]

Answer:

Disaggregation

Explanation:

In a company it is a way to create operational plans that are focused, either by time or by section.

3 0

3 years ago

Technician A says that the distributor cap provides a connection point between the rotor and each individual cylinder plug wire.

Vera_Pavlovna [14]

Answer:

Neither a or b.

Explanation:

The distributor cap is cover which protects internal parts and holds contact between internal rotor and spark plug wires. When inspecting distributor caps there should be some carbon tracking which looks like bright white grease trails.

8 0

3 years ago

Calculate KI for a rectangular bar containing an edge crack loaded in three-point bending where P=35.0 kN, W=50.8 mm, B=25 mm, a

Katyanochek1 [597]

Answer:

$K_{I}=5.21 MPa\sqrt{m}$

Explanation:

given data

Load P = 35 kN

Width of bar W = 50.8 mm

Breadth of bar B = 25 mm

Ratio of crack length to width α = a/W = 0.2

solution

we get here KI for a rectangular bar that is express as

$K_{I} = \frac{6P}{BW}Y\sqrt{\pi a}$ ................................1

here Y is the geometrical function

Y = $\frac{1.12+\alpha (3.43\alpha -1.89)}{1-0.55\alpha}$

Y = $\frac{1.12+0.2(3.43\times 0.2-1.89)}{1-0.55\times 0.2}$

Y = $\frac{0.8792}{0.89}$

Y = 0.9878

so put here value in equation 1

$K_{I} = \frac{6\times 35\times 10^{3}}{0.025\times 0.0508}\times 0.9878\times \sqrt{3.1415\times (0.2\times 0.0508)}$

$K_{I} = 165354.33\times 10^{3}\times 0.9878\times 0.0319$

$K_{I}$ = 5210.45 × 10³ $Pa\sqrt{m}$

$K_{I}$ = 5.21 MPa $\sqrt{m}$

5 0

3 years ago

What are the application of computer modeling in beams

Murljashka [212]

Answer:

This paper discusses recent applications of computer modelling by the author in ... The cantilever beams were connected to a stainless steel torsion tube close to.

Explanation:The use of models in structural engineering is motivated by the work in small boxes performed by Karl … Torsional deformation of ABS beams and connection …

4 0

3 years ago

Why will screws never replace nails​

Why will screws never replace nails