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lesya692 [45]
3 years ago
13

What part of the electromagnetic spectrum can our skin detect?​

Physics
2 answers:
kaheart [24]3 years ago
8 0
The only kinds of radiation they can detect are visible light, which allows them to see, and infrared light, which they feel as warmth on their skin.
inn [45]3 years ago
3 0

Visible and infrared light.

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An ideal solenoid having a coil density of 5000 turns per meter is 10 cm long and carries a current of 4.0
Diano4ka-milaya [45]
The rule that is used to get the strength of magnetic field at the center of solenoid (B) is:
B = <span>µ x n x I where:
</span>µ is the permeability of the medium where the solenoid is based. In this problem, the medium is air which means that µ = <span>µ </span><span>o = 4 pi x 10^-7 Tm/A
</span>I is the current passing (I = 4 amperes)
n is the number of turns per unit length (5000 turns)

Substituting in the mentioned equation, we find that:
B = 4 x 3.14 x 10^-7 x 5000 x 4 = 25.132 mT
5 0
3 years ago
A garage door opener has a power rating of 350 watts. If the door is in operation for 30 seconds, how many joules of energy are
Ksju [112]
Because of the hint we can conclude what equation we need to solve this problem. We have power and duration that means that we need to express energy:

1 joule = 1watt * 1 second
or
E (energy) = P (power) * t (time duration)
E = 350 * 30 = 10500 joules.
7 0
3 years ago
Which equation best expresses the first law of thermodynamics, assuming Q is heat, U is internal energy, and W is work?
devlian [24]

The first law of thermodynamics is expresses by

D. ΔU=Q-W

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All are expressed in Joules.

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5 0
3 years ago
Read 2 more answers
Part A If the velocity of a pitched ball has a magnitude of 47.5 m/s and the batted ball's velocity is 51.5 m/s in the opposite
nalin [4]

Explanation:

Let us assume that the mass of a pitched ball is 0.145 kg.

Initial velocity of the pitched ball, u = 47.5 m/s

Final speed of the ball, v = -51.5 m/s (in opposite direction)

We need to find the magnitude of the change in momentum of the ball and the impulse applied to it by the bat. The change in momentum of the ball is given by :

\Delta p=m(v-u)\\\\\Delta p=0.145\times ((-51.5)-47.5)\\\\\Delta p=-14.355\ kg-m/s

So, the magnitude of the change in momentum of the ball is 14.355 kg-m/s.

Let the the ball remains in contact with the bat for 2.00 ms. The impulse is given by :

J=\dfrac{\Delta p}{t}\\\\J=\dfrac{14.355}{2\times 10^{-3}}\\\\J=7177.5\ kg-m/s

Hence, this is the required solution.

7 0
3 years ago
Unit 5 activity 2 I need answer
saul85 [17]

Answer:

Can you explain more in detail what it is?

Explanation:

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