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Reptile [31]
3 years ago
8

For a constant voltage, how is the resistance related to the current?

Physics
1 answer:
natulia [17]3 years ago
8 0

Answer:

A

Explanation:

R=V/I

IF you double the resistance, it's become:

2R=(1/2)I

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If the velocity of blood flow in the aorta is normally about 0.32 m/s, what beat frequency would you expect if 4.40-MHz ultrasou
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Answer:

The beat frequency is 0.0019 MHz.

Explanation:

Given that,

Velocity = 0.32 m/s

Frequency = 4.40 MHz

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Case (I),

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Using Doppler's effect

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f'=\dfrac{1540-0.32}{1540}\times4.40

f'=4.399\ MHz

Case (II),

Cell is as the source of sound of frequency f' and it moving away from the observer.

Using formula of frequency

f''=\dfrac{v-v_{s}}{v+v_{s}}\times f

f''=\dfrac{1540-0.32}{1540+0.32}\times4.399

f''=4.3971\ MHz

We need to calculate the beat frequency

\Delta f= f'-f''

\Delta f=4.399-4.3971=0.0019\ MHz

Hence, The beat frequency is 0.0019 MHz.

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3 years ago
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