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2 years ago

Pls help What does the image above illustrate?

Chemistry

1 answer:

Furkat [3]2 years ago

5 0

Not 100% if this answers however:

The radium nucleus turns into radon-222 nucleus, itself radioactive, containing two protons and two neutrons less. The disintegration releases 4.6 million electronvolts of energy. The alpha particle carries the 222/226ths of this available energy and the radon 4/226ths.

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Calculate the number of pounds of CO2CO2 released into the atmosphere when a 22.0 gallon22.0 gallon tank of gasoline is burned i

Gnesinka [82]

Answer:

391.28771 pounds of carbon-dioxide was released into the atmosphere when 22.0 gallon tank of gasoline is burned in an automobile engine.

Explanation:

Density of the gasoline ,d= 0.692 g/mL

Volume of gasoline in an tanks,V = 22.0 gallons = 83,279.02 mL

Let mass of the gasoline be M

$Density= \frac{Mass}{Volume}$

M = V × d = 83,279.02 mL × 0.692 g/mL=57,629.081 g

Given that gasoline is primarily octane.

$2C_8H_{18}+25O_2\rightarrow 16CO_2+18H_2O$

Mass of octane burnt in the tank = M = 57,629.081 g

Moles of octane = $\frac{57,629.081 g}{114.08g/mol}=505.1637 mol$

According to reaction, 2 moles of octane gives 16 moles of carbon-dioxide.

Then 505.1637 mol of octane will give:

$\frac{16}{2}\times 505.1637 mol=4,041.3100 mol$ of carbon-dioxide

Mass of 4,041.3100 mol of carbon-dioxide:

4,041.3100 mol × 44.01 g/mol = 177,858.05 g

Mass of carbon-dioxide produced in pounds = 391.28771 pounds

391.28771 pounds of carbon-dioxide was released into the atmosphere when 22.0 gallon tank of gasoline is burned in an automobile engine.

3 0

3 years ago

The state of matter with a specific volume but no definite shape is the ______. state

eimsori [14]

Answer:

C: liquid

Explanation:

Liquid has the set volume as it cannot be compressed or 'expanded' like a gas. However, liquids will take the shape of the container you put them in so their shape can change.

4 0

2 years ago

Read 2 more answers

Suppose that 0.50 grams of barium-131 are administered orally to a patient. Approximately how many milligrams of the barium woul

nalin [4]

Two months later 13.8 milligrams of the barium-131 still be radioactive.

<h3>How is the decay rate of a radioactive substance expressed ? </h3>

It is expressed as:

$A = A_{0} \times (\frac{1}{2})^{t/T}$

where,

A = Amount remaining

A₀ = Initial Amount

t = time

T = Half life

Here

A₀ = 0.50g

t = 2 months = 60 days

T = 11.6 days

Now put the values in above expression we get

$A = A_{0} \times (\frac{1}{2})^{t/T}$

$= 0.50 \times (\frac{1}{2})^{60/11.6}$

$= 0.50 \times (\frac{1}{2})^{5.17}$

= 0.50 × 0.0277

= 0.0138 g

= 13.8 mg [1 mg = 1000 g]

Thus from the above conclusion we can say that Two months later 13.8 milligrams of the barium-131 still be radioactive.

Learn more about the Radioactive here: brainly.com/question/2320811

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Disclaimer: The question was given incomplete on the portal. Here is the complete question.

Question: Suppose that 0.50 grams of ban that 0.50 grams of barium-131 are administered orally to a patient. Approximately many milligrams of the barium would still be radioactive two months later? The half-life of barium-131 is 11.6 days.

3 0

1 year ago

How many moles of aluminum do 4.40×1024 aluminum atoms represent?

zhannawk [14.2K]

For this problem we use the Avogadro's number which is an empirical value that relates the number of particles to the number of moles. Its approximated value is 6.022×10²³ atoms/mole. The solution is as follows:

4.40×10²⁴ aluminum atoms * 1 moles/6.022×10²³ atoms = 7.306

Thus, there are 7.306 moles of aluminum.

3 0

3 years ago

In an exothermic process the surrounding looses heat.<br>False<br>True<br>

SSSSS [86.1K]

Answer:

False

Explanation:

In an exothermic process, the reaction gives off heat, and not takes it in. If it takes it in from the surroundings, then it would be endothermic.

4 0

3 years ago

Read 2 more answers