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3 years ago

Pls help What does the image above illustrate?

Chemistry

1 answer:

Furkat [3]3 years ago

5 0

Not 100% if this answers however:

The radium nucleus turns into radon-222 nucleus, itself radioactive, containing two protons and two neutrons less. The disintegration releases 4.6 million electronvolts of energy. The alpha particle carries the 222/226ths of this available energy and the radon 4/226ths.

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If one mole of a substance has a mass of 56.0 g, what is the mass of 11 nanomoles of the substance? Express your answer in nanog

9966 [12]

Answer:

616,0 ng is the right answer.

Explanation:

You should know that 1 mole = 1 .10^9 nanomoles

Get the rule of three.

1 .10^9 nanomoles ...................... 56.0 gr

11 nanomoles .....................

(11 x 56) / 1 .10^9 nanomoles = 6.16 x 10^-7 gr

Let's convert

6.16 x 10^-7 gr x 1 .10^9 = 616 ngr

8 0

3 years ago

Explain vapour pressure and surface tension What is plasma

worty [1.4K]

Vapor Pressure: Measures how a substance is likey to evaporate

Surface Tension: is the attraction between liquid molecules.

Plasma: is an organic and inorganic substance that is typically found in blood

5 0

3 years ago

Which conversion of energy always occurs in a voltaic cell?

kvasek [131]

(4) chemical energy to electrical energy is the correct answer.
Hope this helps~

4 0

3 years ago

Help plz I rly. Need it

babymother [125]

Answer:

It should be D.

Explanation:

3 0

3 years ago

Calculate the electrical energy per gram of anode material for the following reaction at 298 K:

solmaris [256]

43.8 kJ

<h3>Explanation</h3>

There are two electrodes in a voltaic cell. Which one is the anode?

The lithium atom used to have no oxygen atoms when it was on the reactant side. It gains two oxygen atoms after the reaction. It has gained more oxygen atoms than the manganese atom. Gaining oxygen is oxidation. As a result, lithium is being oxidized.

Oxidation takes place at the anode of a cell. Therefore, the anode of this cell is made of lithium.

Lithium has an atomic mass of 6.94. Each gram of Li would contain 1/6.94 = 0.144 moles of Li atoms. Each Li atom loses one electron in this cell. Therefore, the number of electron transferred, n, equals 0.144 moles for each gram of the anode.

Let $w_\text{max}$ represents the electrical energy produced.

$w_\text{max} = n \cdot F \cdot E_\text{cell}$ , where

n is the number of moles electrons transferred,
F is the Faraday's constant,
E $_\text{cell}$ is the cell potential,

n = 0.144 mol, as shown above, and

F = 96.486 kJ / ( $\text{V} \cdot \text{mol} \; \text{e}^{-}$ ).

Therefore,

$w_\text{max} = n \cdot F \cdot E\\\phantom{w_\text{max}} = 0.144 \times 96.486 \times 3.15 \\\phantom{w_\text{max}} = 43.8 \; \text{kJ}$ .

3 0

3 years ago