Not necessarily.
<h3>Explanation</h3>
Isomers might differ in polarities. They will end up with different physical properties such as melting points.
Example:
- 1,2-dichlorobenzene has a melting point of around -18 ~ -17 degrees celsius. (SynQuest)
- 1,4-dichlorobenzene (with two chlorine opposite to each other on a benzene ring) has a melting point of 52 ~ 54 degrees celsius. (SynQuest)
Both 1,4- and 1,2-dichlorobenzene contains two chlorine atoms connected to a benzene ring. The two molecules are structural isomers.
The two chlorine atoms are adjacent to each other in the 1,2 isomer. The molecule is asymmetric and polar.
The two chlorine align with an axis of symmetry in the 1,4 isomer. The molecule is symmetric. The dipoles would cancel out to produce a nonpolar molecule.
Dipole-dipole interactions are typically stronger than <em>induced</em> dipole<em> </em>in isomers. As a result, the 1,2 isomer has a higher melting point.
Answer:
16.2 J
Explanation:
Step 1: Given data
- Specific heat of liquid bromine (c): 0.226 J/g.K
- Volume of bromine (V): 10.0 mL
- Initial temperature: 25.00 °C
- Final temperature: 27.30 °C
- Density of bromine (ρ): 3.12 g/mL
Step 2: Calculate the mass of bromine
The density is equal to the mass divided by the volume.
ρ = m/V
m = ρ × V
m = 3.12 g/mL × 10.0 mL
m = 31.2 g
Step 3: Calculate the change in the temperature (ΔT)
ΔT = 27.30 °C - 25.00 °C = 2.30 °C
The change in the temperature on the Celsius scale is equal to the change in the temperature on the Kelvin scale. Then, 2.30 °C = 2.30 K.
Step 4: Calculate the heat required (Q) to raise the temperature of the liquid bromine
We will use the following expression.
Q = c × m × ΔT
Q = 0.226 J/g.K × 31.2 g × 2.30 K
Q = 16.2 J
You take the temperature and follow these steps:
Take the temperature in farenheit, suntract 32, then multiply that by 5, and divide by 9.
I think it is 4. Covalent compound which is named carbon dioxide.
