The watt is the standard unit of measurement for?
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Prontosil is a compound produced by the coupled reaction of an aryldiazonium ion and an aromatic compound.
<h3>What are diazonium compounds?</h3>
These are organic compounds in which there are ionic interactions between the azo group (-N₂⁺) and an anion X⁻.
The general structure is RN₂⁺X⁻.
- R is the lateral chain that might be an aromatic ring, among other options.
- N₂⁺ is the azo group
- X⁻ is the anion
The azo group characterizes as being unstable and reactive. This property is because one of the N atoms has a positive charge.
-N⁺≡ N
<h3>What is the coupling reaction of aryldiazonium compounds?</h3>Aryldiazonium salt reactions can occur in two ways,
- Substitution reactions
- Coupling reactions
Coupling reactions are the aromatic electrophilic substitution, where the aryldiazonium ion acts as an electrophile for an activated aromatic compound to attack it.
The coupling reaction occurs at the azo group level.
In the exposed example,
- the benzene ring with sulfur bonded to oxygen atoms is the coupling component
- the benzene ring with NH₂ and the azo group is the diazonium ion
In the attached files you will find the drawings.
You can learn more about diazonium compounds at
27,586
<h3>Further explanation</h3><u>Given:</u>
A single gold atom has a diameter of
From a reference, the Rutherford gold foil used in his scattering experiment had a thickness of approximately
<u>Question:</u>
How many atoms thick were Rutherford's foil?
<u>The Process:</u>
Convert thickness from mm to cm.
The number of atoms is calculated from gold foil thickness divided by the atomic diameter.
Therefore, we get an atomic thickness of 27,586 atoms.
<u>Notes:</u>
- In 1909-1910, Ernest Rutherford with two of his assistants, namely Hans Geiger and Ernest Marsden, conducted a series of experiments to find out more about the arrangement of atoms. They fired at a very thin gold plate with high-energy alpha particles.
- One of their observations is that a small portion of alpha particles are reflected. This greatly surprised Rutherford. The reflected alpha particle must have hit something very dense in the atom. This fact is incompatible with the atomic model proposed by J.J. Thomson where the atoms are described as homogeneous in all parts with electrons and protons evenly distributed.
- In 1911, Rutherford was able to explain the scattering of alpha rays by proposing ideas about atomic nuclei. According to him, most of the mass and positive charge of atoms are concentrated at the center of the atom, hereinafter referred to as the nucleus.
- The energy density of the stored energy brainly.com/question/9617400
- The theoretical density of platinum which has the FCC crystal structure. brainly.com/question/5048216
- Compound microscope brainly.com/question/4000241
Keywords: if a single gold atom, has a diameter of 2.9 x 10⁻⁸ cm, how many, atoms thick, Rutherford's foil, his scattering experiment