<span>Part of a rocket's propulsion system includes a chemical oxidizer, either in the form of liquid oxygen, the solid ammonium perchlorate, or the propulsion/oxidizer mixture Hydrazine. No outside source of oxygen is needed.
Steering is accomplished by "gimbaled" rocket nozzles which change the direction of the blast to keep the rocket on course. Once in space and in orbit, slight changes in orientation is made by small rockets placed around the craft that spurt little gas jets to nudge the craft into the desired position.</span><span>
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Answer:
856,68 J/gram
Explanation:
We know that the variaton of temperature of 1K is equal to 1°C
so if the ΔT is 3.55°C, it is 3.55K.
so
403 J - 1 K
x - 3.55K
X= 403 * 3.55 = 1430,65 J
1.670 g - 1430,65 J
1 g - y
y = 
= 856,68 J
Answer:
Why ? Because 1 molecule of H2SO4 gives 2 H+ ions per molecule while only one H+ ion is required to neutralize 1 molecule of KOH. So, 1 molecule of H2SO4 can neutralize 2 molecules of KOH. Hence, we would require 525 ml of 0.03 M H2SO4 to neutralize 525 ml of 0.06 M KOH. How will we prepare 525 ml of 0.03 M H2SO4 ?
Explanation:
Now, we have 0.025 M H2SO4 and we do not know how much volume we have.
We will use the standard N1 X V1 = N2 X V2 for this calculation.
N1=0.025 M; V1=unknown; N2=0.03 M and V2=525 ml.
So V1= (0.03 X 525)/(0.025) = 630 ml.
Answer:
C is the reaction intermediate.
Explanation:
A reaction intermediate is a molecular structure that is formed during the reaction but then is converted in the final products.
Usually, these reaction intermediates are unestable and, for that reason, the lifetime of these structures is low.
In the reaction, you can see in the first step C is produced, but also, in the second step reacts producing D. As is produced and, immediately consumed,
<h3>C is the reaction intermediate.</h3>
Answer:
K.E = 25 J
Explanation:
Given data:
Mass of ball = 0.5 g
Velocity of ball = 10 m/s
Kinetic energy = ?
Solution:
Formula:
K.E = 1/2 mv²
m = mass
v = velocity
Now we will put the values in formula.
K.E = 1/2 mv²
K.E = 1/2× 0.5kg × (10m/s)²
K.E = 1/2 ×0.5kg × 100m²/s²
K.E = 25 Kg.m²/s²
Kg.m²/s² = J
K.E = 25 J
