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2 years ago

What is the mass ratio of aluminum to oxygen in aluminum oxide, Al2O3?

Chemistry

1 answer:

liubo4ka [24]2 years ago

5 0

Answer:

9 : 8

Explanation:

Aluminum oxide has the following formula Al₂O₃.

Next, we shall determine the mass of Al and O₂ in Al₂O₃. This can be obtained as follow:

Mass of Al in Al₂O₃ = 2 × 27 = 54 g

Mass of O₂ in Al₂O₃ = 3 × 16 = 48 g

Finally, we shall determine the mass ratio of Al and O₂. This can be obtained as follow:

Mass of Al = 54 g

Mass of O₂ = 48 g

Mass of Al : Mass of O₂ = 54 : 48

Mass of Al : Mass of O₂ = 54 / 48

Mass of Al : Mass of O₂ = 9 / 8

Mass of Al : Mass of O₂ = 9 : 8

Therefore, the mass ratio of Al and O₂ in Al₂O₃ is 9 : 8

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Explain the difference between a physical property and chemical property. Give examples of each.

MA_775_DIABLO [31]

A physical property is what a substance is like; it's directly observable. On the other hand, a chemical property is how a substance behaves; its reactivity.

Examples of a physical property are: color, texture, boiling point, freezing point, and melting point.

Examples of a chemical property are: flammability, combustion, and formation of a precipitate.

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2 years ago

1. Which of the following is a correctly written thermochemical equation?

WITCHER [35]

Explanation:

1. Thermochemical equation is balance stoichiometric chemical equation written with the phases of the reactants and products in the brackets along with the enthalpy change of the reaction.

The given correct thermochemical reactions are:

$Fe(s)+O_2(g)\rightarrow Fe_2O_3(s),\Delta H = 3,926 kJ
$

$C_3H_8(g)+5O_2 (g)\rightarrow 3CO_2 (g)+4H_2O(l),\Delta H= 2,220 kJ/mol$

2. Phase change affect the value of the enthalpy change of the thermochemical equation. This is because change in phase is accompanied by change in energy. For example:

$H_2O(s)\rightarrow H_2O(g),\Delta H_{s}=51.1 kJ/mol$

$H_2O(l)\rightarrow H_2O(g),\Delta H_{v}=40.65 kJ/mol$

In both reaction phase of water is changing with change in energy of enthalpy of reaction.

7 0

3 years ago

Read 2 more answers

What is the osmotic pressure of a solution made from 22.3 g of methanol (MM = 32.04 g/mol) that was added to water to make 321 m

xxMikexx [17]

Answer: The osmotic pressure of a solution is 53.05 atm

Explanation:

To calculate the concentration of solute, we use the equation for osmotic pressure, which is:

$\pi=iMRT$

Or,

$\pi=i\times \frac{\text{Mass of solute}\times 1000}{\text{Molar mass of solute}\times \text{Volume of solution (in mL)}}\times RT$

where,

$\pi$ = osmotic pressure of the solution = ?

i = Van't hoff factor = 1 (for non-electrolytes)

Mass of solute (methanol) = 22.3 g

Volume of solution = 321 mL

R = Gas constant = $0.0821\text{ L.atm }mol^{-1}K^{-1}$

T = temperature of the solution = $25^oC=[273+25]=298K$

Putting values in above equation, we get:

$\pi=1\times \frac{22.3\times 1000}{32.04\times 321}\times 0.0821\text{ L.atm }mol^{-1}K^{-1}\times 298K$

$\pi=53.05atm$

Hence, the osmotic pressure of a solution is 53.05 atm

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2 years ago

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BartSMP [9]

Answer:

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2 years ago

What happens when gasoline is used to power a vehicle?

Romashka [77]

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3 years ago