Answer is: concentration of hydrogen iodide is 6 M.
Balanced chemical reaction: H₂(g) + I₂(g) ⇄ 2HI(g).
[H₂] = 0.04 M; equilibrium concentration of hydrogen.
[I₂] = 0.009 M; equilibrium concentration of iodine.
Keq = 1·10⁵.
Keq = [HI]² / [H₂]·[I₂].
[HI]² = [H₂]·[I₂]·Keq.
[HI]² = 0.04 M · 0.009 M · 1·10⁵.
[HI]² = 36 M².
[HI] = √36 M².
[HI] = 6 M.
It is fact that
6.023
×
10
23
formula units of barium nitrate have a mass of
16.6*10^23
⋅
g
. This is what we specify when we say molar mass. And thus the mass of
5.30
×
10
22
formula units of barium nitrate is the quotient multiplied by the molar mass:
5.30
×
10
22
6.023
×
10
23
m
o
l
×
16.6*10^23
⋅
g
⋅
m
o
l
−
1
Answer:
44,901 kilo Joule heat is released when 
grams of ammonia is produced.
Explanation:
Moles of ammonia gas produced :
According to reaction, when 2 moles of ammonia are produced 9.18 kilo joules of energy is also released.
So, When 978.235 moles of ammonia gas is produced the energy released will be:
(negative sign indicates that energy is released as heat)
44,901 kilo Joule heat is released when grams of ammonia is produced.
