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ololo11 [35]
3 years ago
7

Which is the simplified form of the expression (6 Superscript negative 2 Baseline times 6 Superscript 5 Baseline) Superscript ne

gative 3?
Mathematics
2 answers:
lapo4ka [179]3 years ago
8 0

-3

Step-by-step explanation:

(6-2* 6+5)-2

-BARSIC- [3]3 years ago
8 0

Answer:

1/6^9

Step-by-step explanation:

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I don't really understand this??....​
Mila [183]

Answer:

Part 1

its asking you to find the slope of the given lines by using the points that they have plotted on the lines

first you need to figure out what the points are, then insert it into the formula

the formula for this would be \frac{Y2- Y1}{X2-X1}

Part 2:

its asking you to find the slope using the points that are written in each box

again, just substitute it into the formula

the formula for this would be \frac{Y2- Y1}{X2-X1}

5 0
3 years ago
What is the explicit formula for the sequence below?<br><br> 4, -12, 36, -108 ...
liubo4ka [24]

Answer:x ×-3

Step-by-step 4×-3= -12

-12 × -3= 36

and so on

6 0
3 years ago
Read 2 more answers
10. Three kinds of teas are worth $4.60 per pound, $5.75 per pound, and $6.50 per pound. They are to be
zepelin [54]

Answer:

The mass of the $4.60/lb tea that should be used in the mixture is 10 lb

The mass of the $5.75/lb tea that should be used in the mixture is 8 lb

The mass of the $6.50/lb tea that should be used in the mixture is 2 lb

Step-by-step explanation:

The parameters of the question are;

The worth of the three teas are

Tea A = $4.60/lb

Tea B = $5.75/lb

Tea C = $6.50/lb

The mass of the mixture of the three teas = 20 lb

The worth of the mixture of the three teas = $5.25 per pound = $5.25/lb

The amount of the $4.60 in the mixture = The sum of the amount of the other two teas

Therefore, given that the mass of the mixture = 20 lb, we have in the mixture;

The mass of tea A + The mass of Tea B + The mass of Tea C = 20 lb

The mass of tea A = The mass of Tea B + The mass of Tea C

Therefore;

The mass of tea A + The mass of tea A = 20 lb

2 × The mass of tea A in the mixture = 20 lb

The mass of tea A in the mixture = 20 lb/2 = 10 lb

The mass of tea A in the mixture = 10 lb

The mass of Tea B + The mass of Tea C = The mass of tea A = 10 lb

The mass of Tea B + The mass of Tea C = 10 lb

The mass of Tea B  = 10 lb - The mass of Tea C

Where the mass of Tea C in the mixture = x, we have;

The mass of Tea B in the mixture = 10 lb - x

The cost of the 10 lb of tea A = 10 × $4.60 = $46.0

The worth of the tea mixture = 20 × $5.25 = $105

The worth of the remaining 10 lb of the mixture comprising of tea A and tea B is given as follows;

The worth of Tea B + The worth of Tea C in the mixture = $105.00 - $46.00 = $59.00

Therefore, we have;

x lb × $6.50/lb + (10 - x) lb × $5.75/lb = $59.00

x × $6.50 - x × $5.75 + $57.50 = $59.00

x × $0.75 = $59.00 -  $57.50 = $1.50

x =  $1.50/$0.75 = 2 lb

∴ The mass of Tea C in the mixture = 2 lb

The mass of Tea B in the mixture = 10 lb - x = 10 lb - 2 lb = 8 lb

The mass of Tea B in the mixture = 8 lb

Therefore, since we have;

Tea A = $4.60/lb

Tea B = $5.75/lb

Tea C = $6.50/lb

The mass of tea A in the mixture = 10 lb

The mass of tea B in the mixture = 8 lb

The mass of tea C in the mixture = 2 lb, we find;

The mass of the $4.60/lb tea that should be used in the mixture = 10 lb

The mass of the $5.75/lb tea that should be used in the mixture = 8 lb

The mass of the $6.50/lb tea that should be used in the mixture = 2 lb.

6 0
3 years ago
Which equation represents the volume of a cone with the same base and height as the cylinder below? A cylinder with a height k a
Igoryamba

Answer: The correct answer is Volume Cone = one-third pi t squared k

Step-by-step explanation: The first important detail to note here is that both cylinder and cone have the same base and the same height This implies that when writing out the formula for calculating the volume of either of the two shapes, the radius and the height will be the same number or value.

The volume of a cylinder is given as;

Volume cylinder = pi x r squared x h (that is πr²h)

Also the volume of a cone is given as;

Volume cone = one-third x pi x r squared x h (that is 1/3*πr²h)

However, the variables have been changed such that the radius r is now represented by t while the height h is now represented by k.

Therefore the volume of the cone should now be re-written as;

Volume cone = one-third pi t squared k <em>(that is 1/3 *πt²k)</em>

3 0
3 years ago
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Marking brainliest <br><br> Please help
Ugo [173]
I think the answer is plus bc you need to add
5 0
3 years ago
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