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kati45 [8]
3 years ago
9

A student uses the periodic table to construct a model that uses a simple diagonal arrow to depict decreasing electronegativity.

Where should the arrow point to indicate the lowest electronegativity of all the elements?
Chemistry
1 answer:
Galina-37 [17]3 years ago
5 0

Answer:

helium

Explanation:

helium has the highest ionization energy level

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The density of Nitrogen (N2) gas in a 4.32 L container at our
scoundrel [369]

Answer:

δ N2(g) = 1.1825 g/L

Explanation:

  • δ ≡ m/v
  • Mw N2(g) = 28.0134 g/mol

ideal gas:

  • PV = RTn

∴ P = (837 torr)×( atm/760 torr) = 1.1013 atm

∴ T = 45.0 °C + 273.15 = 318.15 K

∴ R = 0.082 atm.L/K.mol

⇒ n/V = P/R.T

⇒ n/V = (1.1013 atm) / ((0.082 atm.L/K.mol)(318.15 k))

⇒ n/V = 0.0422 mol/L

⇒ δ N2(g) = (0.042 mol/L)×(28.0134 g/mol) = 1.1825 g/L

5 0
3 years ago
The ionization constant (Ka) of HF is 6.7 X 10 ^-4. Which of the following is true in a 0.1 M solution of this acid?
spin [16.1K]
The ionization equation is:

HF ⇄ H(+) + F(-)

The ionization constant is Ka = [H(+)] * [H(-)] / [HF]

=> [H(+)] * [F(-)] = Ka * [HF]

Given that Ka < 1

[H(+)] * [F(-)] < [HF]

Which is [HF] >  [H(+)] * [F(-)] the option a. fo the list of choices.
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3 years ago
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Calculate the change in pH when 71.0 mL of a 0.760 M solution of NaOH is added to 1.00 L of a solution that is 1.0O M in sodium
Eddi Din [679]

Explanation:

It is known that pK_{a} value of acetic acid is 4.74. And, relation between pH and pK_{a} is as follows.

                    pH = pK_{a} + log \frac{[CH_{3}COOH]}{[CH_{3}COONa]}

                          = 4.74 + log \frac{1.00}{1.00}

So, number of moles of NaOH = Volume × Molarity

                                                   = 71.0 ml × 0.760 M

                                                    = 0.05396 mol

Also, moles of  CH_{3}COOH = moles of CH_{3}COONa

                                          = Molarity × Volume

                                          = 1.00 M × 1.00 L

                                          = 1.00 mol

Hence, addition of sodium acetate in NaOH will lead to the formation of acetic acid as follows.

            CH_{3}COONa + NaOH \rightarrow CH_{3}COOH

Initial :    1.00 mol                                  1.00 mol

NaoH addition:               0.05396 mol

Equilibrium : (1 - 0.05396 mol)    0           (1.00 + 0.05396 mol)

                    = 0.94604 mol                       = 1.05396 mol

As, pH = pK_{a} + log \frac{[CH_{3}COONa]}{[CH_{3}COOH]}

               = 4.74 +  log \frac{0.94604}{1.05396}

               = 4.69

Therefore, change in pH will be calculated as follows.

                         pH = 4.74 - 4.69

                               = 0.05

Thus, we can conclude that change in pH of the given solution is 0.05.

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Convert 1.580 hectoliters to deciliters.<br><br> liters
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Answer:

1580 decilliters

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