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svet-max [94.6K]
3 years ago
11

In which crash did the puck experience a stronger force? WHY/

Engineering
1 answer:
Serggg [28]3 years ago
3 0
I cant see the words
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Choose the true statement from those shown below: A Merchant Account allows you to use SSL on your web site. Disadvantages of us
Slav-nsk [51]

Answer:

The answer is A. that is, a merchant account allows you to use SSL on your website.

Explanation:

SSL means Secure Sockets Layer and this is an encryption-based Internet security protocol.

For an e-commerce merchant website or account, it is advised that an SSL package be installed to prevent any potential loss of private information.

For this reason, a merchant account allows use of SSL on your website because this also boost the confidence of client and customers visiting the website to purchase products.

7 0
3 years ago
What is the tolerance of number 4?
Kamila [148]

Answer:

Answer: ±0.02 units or 20±0.02 units or 19.98-20.02 units depending on how they prefer its written (typically the first or second one)

Explanation:

says on the sheet. Unless otherwise stated 0.XX = ±0.02 tolerance

(based on image sent in other post)

5 0
3 years ago
What factors determine tire inflation pressure?
Virty [35]

Answer:

Tire inflation can be caused by temperature and speed :)

6 0
3 years ago
Please explain what is the difference between engineering stress and true stress in a tensile test?
NNADVOKAT [17]

Answer:

Explanation:

Engineering Stress is defined as Load applied to the original cross-sectional area which we have taken in the start.

True stress is defined as the load divided by area of cross-section of specimen at that instant.

Engineering stress  and true stress can be expressed by relation

\sigma _T=\sigma _E\left ( 1+\epsilon _E\right )

Where

\sigma _T=True\ stress

\sigma _E=Engineering\ stress

\epsilon _E=Engineering\ Strain

6 0
4 years ago
A First Stage in a turbine receives steam at 10 MPa, 800 C with an exit pressure of 800 KPa. Assume the stage is adiabatic and r
9966 [12]

Answer

given,

P₁  = 10 MPa                 T₁ = 800

P₂ = 800 KPa               T₂ = ?

Using formula

\dfrac{T_2}{T_1} = (\dfrac{P_2}{P_1})^{\dfrac{n-1}{n}}

For steam   n = 1.33                    

\dfrac{T_2}{800+273} = (\dfrac{800\times 10^{3}}{10\times 10^{6}})^{\dfrac{1.33-1}{1.33}}

T₂ = 573.368 K                    

T₂ = 573.368 - 273 = 300.368 °C

W = \dfrac{P_1V_1-P_2V_2}{n-1}

          =\dfrac{mR(T_1-T_2)}{n-1}

          =\dfrac{1\times 0.287\times (800 - 300.368)}{1.33-1}

      W = 434.53 kJ/kg

7 0
3 years ago
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