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stiks02 [169]
2 years ago
12

What are the characteristics of carbon fibre?

Engineering
1 answer:
nexus9112 [7]2 years ago
5 0

Answer:

high tensile strenth

high stiffness

Explanation:

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In fully developed laminar flow in a circular pipe the velocity at R/2 (mid-way between the wall surface and the centerline) is
Butoxors [25]

Answer:

u_{max} = 17.334\,\frac{m}{s}

Explanation:

Let consider that velocity profile inside the circular pipe is:

u(r) = 2\cdot U_{avg} \cdot \left(1 - \frac{r^{2}}{R^{2}}  \right)

The average speed at r = \frac{1}{2} \cdot R is:

U_{avg} = \frac{13\,\frac{m}{s} }{2\cdot \left(1-\frac{1}{4}  \right)}

U_{avg} = 8.667\,\frac{m}{s}

The velocity at the center of the pipe is:

u_{max} = 2\cdot U_{avg}

u_{max} = 17.334\,\frac{m}{s}

6 0
2 years ago
Read 2 more answers
A hub a signal that refreshes the signal strength.
vekshin1

Answer:You are a network engineer. While moving a handheld wireless LAN device, you notice that the signal strength increases when the device is moved from a ...

Explanation:

7 0
2 years ago
Close to 16 billion pounds of ethylene glycol (EG) were produced in 2013. It previously ranked as the twenty-sixth most produced
bekas [8.4K]

Answer:

a) 0.684

b) 0.90

Explanation:

Catalyst

EO + W → EG

<u>a) calculate the conversion exiting the first reactor </u>

CAo = 16.1 / 2   mol/dm^3

Given that there are two stream one  contains 16.1 mol/dm^3 while the other contains   0.9 wt% catalyst

Vo = 7.24 dm^3/s

Vm = 800 gal = 3028 dm^3

hence Im = Vin/ Vo = (3028 dm^3) / (7.24dm^3/s) = 418.232 secs = 6.97 mins

next determine the value of conversion exiting the reactor ( Xai ) using the relation below

KIm = \frac{Xai}{1-Xai}  ------ ( 1 )

make Xai subject of the relation

Xai = KIm / 1 + KIm  ---  ( 2 )

<em>where : K = 0.311 ,  Im = 6.97   ( input values into equation 2 )</em>

Xai = 0.684

<u>B) calculate the conversion exiting the second reactor</u>

CA1 = CA0 ( 1 - Xai )

therefore CA1 = 2.5438 mol/dm^3

Vo = 7.24 dm^3/s

To determine the value of the conversion exiting the second reactor  ( Xa2 ) we will use the relation below

XA2 = ( Xai + Im K ) / ( Im K + 1 ) ----- ( 3 )

<em> where : Xai = 0.684 , Im = 6.97,  and K = 0.311  ( input values into equation 3 )</em>

XA2 = 0.90

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4 0
3 years ago
Do YOU have big brain?
KatRina [158]

Answer:

The average adult brain is about 15 cm and weighs from 1300 to 1400 grams. So around 3 pounds

So not yet, im not an adult yet

5 0
3 years ago
Read 2 more answers
What mass of LP gas is necessary to heat 1.4 L of water from room temperature (25.0 ∘C) to boiling (100.0 ∘C)? Assume that durin
DochEvi [55]

Answer:

m_{LP}=0.45\,kg

Explanation:

Let assume that heating and boiling process occurs under an athmospheric pressure of 101.325 kPa. The heat needed to boil water is:

Q_{water} = (1.4\,L)\cdot(\frac{1\,m^{3}}{1000\,L} )\cdot (1000\,\frac{kg}{m^{3}} )\cdot [(4.187\,\frac{kJ}{kg\cdot ^{\textdegree}C} )\cdot (100^{\textdegree}C-25^{\textdegree}C)+2257\,\frac{kJ}{kg}]

Q_{water} = 3599.435\,kJ

The heat liberated by the LP gas is:

Q_{LP} = \frac{3599.435\,kJ}{0.16}

Q_{LP} = 22496.469\,kJ

A kilogram of LP gas has a minimum combustion power of 50028\,kJ. Then, the required mass is:  

m_{LP} = \frac{22496.469\,kJ}{50028\,\frac{kJ}{kg} }

m_{LP}=0.45\,kg

6 0
2 years ago
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