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3 years ago

What is referred to as "Pyroelectric" materials?

Engineering

1 answer:

aliina [53]3 years ago

5 0

Answer and Explanation:

Pyroelectric material

Pyroelectric materials have special property of generating potential difference (although it is very less ) when these material are treated with heat or when celled down.

The potential difference generated is for very less time

The generation of potential difference is due to change in position of atoms after heating or cooling.

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Electrical circuits must be locked-out/tagged-out before electricians work on any equipment. Is this true or false?

dybincka [34]

Answer:

true

Explanation:

Equipment that are "locked-out/tagged-out" prevent the electrician from being electrocuted or attaining a serious injury in relation to it. Locking out an equipment prevents it from releasing its energy because such energy can be hazardous to the electrician. There are instances when the equipment accidentally starts up, thus, it is essential that the equipment's source of energy is isolated.

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3 years ago

In surveying , supposing we can not pull the tape because it is passing through a shallow river. What will i do to obtain an acc

natulia [17]

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Explanation:

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2 years ago

In multi-grade oil what is W means?

irga5000 [103]

Answer:

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Explanation:

The “W”/winter viscosity grades describe the oil's viscosity under cold temperature engine starting conditions. There's a Low Temperature Cranking Viscosity which sets a viscosity requirement at various low temperatures to ensure that the oil isn't too thick so that the starter motor can't crank the engine over.

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3 years ago

Which of the following color schemes is composed of hues next to eachother on the color wheel ?

Softa [21]

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3 years ago

Water at a pressure of 3 bars enters a short horizontal convergent channel at 3.5 m/s. The upstream and downstream diameters of

earnstyle [38]

Answer:

The pressure reduces to 2.588 bars.

Explanation:

According to Bernoulli's theorem for ideal flow we have

$\frac{P}{\gamma _{w}}+\frac{V^{2}}{2g}+z=constant$

Since the losses are neglected thus applying this theorm between upper and lower porion we have

$\frac{P_{u}}{\gamma _{w}}+\frac{V-{u}^{2}}{2g}+z_{u}=\frac{P_{L}}{\gamma _{w}}+\frac{V{L}^{2}}{2g}+z_{L}$

Now by continuity equation we have

$A_{u}v_{u}=A_{L}v_{L}\\\\\therefore v_{L}=\frac{A_{u}}{A_{L}}\times v_{u}\\\\v_{L}=\frac{d^{2}_{u}}{d^{2}_{L}}\times v_{u}\\\\\therefore v_{L}=\frac{2500}{900}\times 3.5\\\\\therefore v_{L}=9.72m/s$

Applying the values in the Bernoulli's equation we get

$\frac{P_{L}}{\gamma _{w}}=\frac{300000}{\gamma _{w}}+\frac{3.5^{2}}{2g}-\frac{9.72^{2}}{2g}(\because z_{L}=z_{u})\\\\\frac{P_{L}}{\gamma _{w}}=26.38m\\\\\therefore P_{L}=258885.8Pa\\\\\therefore P_{L}=2.588bars$

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3 years ago