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forsale [732]
3 years ago
8

Ok so lets say that you are in love with this girl u r talking to and she just got out of a bad relationship and u want to get w

ith her but she wants to wait. Do you wait on her or just keep her in mind and go on and find someone new?
Chemistry
2 answers:
Irina18 [472]3 years ago
3 0

if you really liked this person then it would be no discussion if you really do like this person then you want to wait

patriot [66]3 years ago
3 0

Answer:

Wait on her

Explanation:

Talk to her and try to be friends with her. Let her talk about the relationship she came out of and see if she wants to meet someone new. If she seems interested in you, take that chance. If she seems to be interested in someone else, find someone new.

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What is the density of the black hole
Karolina [17]

the density of a black hole is 22.61 g/cm3 i think

7 0
3 years ago
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How many molecules is 0.360 mole of water?
Nikitich [7]

Answer: 2.17 x 10^23 molecules

Explanation:

1mole of H2O contains 6.02x10^23 molecules.

Therefore 0.360mole of H2O will contain = 0.36 x 6.02x10^23 = 2.17 x 10^23 molecules

4 0
2 years ago
Purple Group Header Warm-Up Why can I smell a chocolate bar even though it is a solid? Read the description of the office myster
likoan [24]

Answer:

The smell of a chocolate is from the presence of volatile compounds present in the chocolate bar which at room temperature readily changes phase from solid to liquid to vapor or gas

Explanation:

There are nearly 600 identified compounds present in a chocolate bar and out of these, there are volatile components which gives the chocolate bar its distinctive aroma.

These volatile chocolate contents readily change phase from solid to vapor, with very short duration liquid phase.

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4 0
3 years ago
What is the volume of an oxygen tank if it contains 12 moles of oxygen at 273 K under 75 kPa?
Zina [86]
Given:
n = 12 moles of oxygen
T = 273 K, temperature
p = 75 kPa, pressure

Use the ideal gas law, given by
pV=nRT \\ or \\  V= \frac{nRT}{p}
where
V = volume
R = 8.3145 J/(mol-K), the gas constant

Therefore,
V= \frac{(12\,mol)(8.3145\, \frac{J}{mol-K} )(273\,K)}{75 \times 10^{3} \, Pa}= 0.3632\,m^{3}

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5 0
3 years ago
Complete combustion of 3.20g of a hydrocarbon produced 9.69g of CO2 and 4.96g of H2O. What is the empirical formula for the hydr
vlabodo [156]

Let empirical formula for hydrocarbon is CxHy

it will undergo combustion as

CxHy + (x + y/4) O2  ---> xCO2 + (y/2 )H2O

Given that mass of CO2 produced = 9.69 g

So moles of CO2 produced = 9.69 / 44 = 0.22 moles

So moles of carbon present = 0.22 moles

mass of H2O produced = 4.96 g

Moles of H2O produced = mass / molar mass = 4.96 / 18 = 0.28 moles

So moles of H present = 2 X 0.28 = 0.56 moles

Let us divided the moles of each with lowest value of moles

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Multiplying with two to get whole number

the ratio of carbon and hydrogen will be : C:H = 2:5

empirical formula : C2H5


4 0
3 years ago
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