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forsale [732]
3 years ago
8

Ok so lets say that you are in love with this girl u r talking to and she just got out of a bad relationship and u want to get w

ith her but she wants to wait. Do you wait on her or just keep her in mind and go on and find someone new?
Chemistry
2 answers:
Irina18 [472]3 years ago
3 0

if you really liked this person then it would be no discussion if you really do like this person then you want to wait

patriot [66]3 years ago
3 0

Answer:

Wait on her

Explanation:

Talk to her and try to be friends with her. Let her talk about the relationship she came out of and see if she wants to meet someone new. If she seems interested in you, take that chance. If she seems to be interested in someone else, find someone new.

You might be interested in
3. Methyl acetate is hydrolyzed at 25 oC in acidic environment. Aliquots of equal volume are removed and titrated with NaOH solu
avanturin [10]

Solution :

Time (sec)       Volume of NaOH (mL)

339                           26.23

1242                         27.80

2745                        29.70

4546                         3.81

$\infty$                               39.81

Now the example of the first order kinetics w.r.t volumetric analysis is :

$k=\frac{2.303}{t} \log \left(\frac{v_{\infty}-v_0}{v_{\infty}- v_t}\right)$

Here, $v_{\infty}= \text{ volume at }\infty = 39.81$

$v_{t}= \text{ volume at time 't' } = 27.80$

$v_0$ = volume at time 0 = 0

Since the interval is not constant, we take the time interval as

$=\frac{903+1503+1801}{3}$

$=\frac{4207}{3}$

= 1402.3333

≈  1402 seconds

$k=\frac{2.303}{1402} \log \left(\frac{39.81-0}{39.81-27.80}\right)$

  $=(0.001643) \log \left(\frac{39.81}{10.01}\right)$

  = 0.001643 x 0.52045

  = 0.00082

  $= 8.55 \times 10^{-4} \ sec^{-1}$

Therefore, the first order rate constant is k $= 8.55 \times 10^{-4} \ sec^{-1}$.

5 0
2 years ago
How many moles of glucose does 1.2 x 10^24 molecules represent
sammy [17]
<h3>Answer:</h3>

2.0 mol C₆H₁₂O₆

<h3>General Formulas and Concepts:</h3>

<u>Math</u>

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right

<u>Chemistry</u>

<u>Atomic Structure</u>

  • Avogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.

<u>Stoichiometry</u>

  • Using Dimensional Analysis
<h3>Explanation:</h3>

<u>Step 1: Define</u>

1.2 × 10²⁴ molecules C₆H₁₂O₆ (glucose)

<u>Step 2: Identify Conversions</u>

Avogadro's Number

<u>Step 3: Convert</u>

  1. Set up:                               \displaystyle 1.2 \cdot 10^{24} \ molecules \ C_6H_{12}O_6(\frac{1 \ mol \ C_6H_{12}O_6}{6.022 \cdot 10^{23} \ molecules \ C_6H_{12}O_6})
  2. Divide:                                                                                                                      \displaystyle 1.99269 \ mol \ C_6H_{12}O_6

<u>Step 4: Check</u>

<em>Follow sig fig rules and round. We are given 2 sig figs.</em>

1.99269 mol C₆H₁₂O₆ ≈ 2.0 mol C₆H₁₂O₆

3 0
3 years ago
Can somebody explain step by step how to solve decomposition reactions?
SVEN [57.7K]
A decomposition reaction occurs when one reactant breaks down into two or more products. It can be represented by the general equation:

AB → A + B
In this equation, AB represents the reactant that begins the reaction, and A and B represent the products of the reaction. The arrow shows the direction in which the reaction occurs.
7 0
3 years ago
What refers to the attractive forces that exist between molecules?​
CaHeK987 [17]
Intermolecular forces are the forces of attraction or repulsion which act between neighboring particles (atoms, molecules, or ions ). These forces are weak compared to the intramolecular forces, such as the covalent or ionic bonds between atoms in a molecule.
8 0
3 years ago
How many molecules are there in a 1.43 mole sample of H2O2?
SIZIF [17.4K]
One mole of hydrogen peroxide contains 6.02 x 10^23 molecules of hydrogen peroxide. And each molecule contains 4 atoms, so the answer is 4 x 6.02 x 10^23.
5 0
3 years ago
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