Answer:
r = 6.4 cm
Explanation:
F = GMm/r²
r = √(GMm/F)
r = √((6.674e-11)(6.2e5)(13e3)/130)
r = 0.06432... m
Those are some high density materials!
Answer:
![v_x = 4.87 m/s](https://tex.z-dn.net/?f=v_x%20%3D%204.87%20m%2Fs)
Explanation:
Height of the cliff is given as
![h = 37.1 m](https://tex.z-dn.net/?f=h%20%3D%2037.1%20m)
now the time taken by the diver to hit the surface is given as
![h = \frac{1}{2}gt^2](https://tex.z-dn.net/?f=h%20%3D%20%5Cfrac%7B1%7D%7B2%7Dgt%5E2)
![37.1 = \frac{1}{2}(9.8)t^2](https://tex.z-dn.net/?f=37.1%20%3D%20%5Cfrac%7B1%7D%7B2%7D%289.8%29t%5E2)
![t = 2.75 s](https://tex.z-dn.net/?f=t%20%3D%202.75%20s)
Now in the same time it has to cover a distance of 13.39 m
so the speed in horizontal direction is given as
![v_x = \frac{x}{t}](https://tex.z-dn.net/?f=v_x%20%3D%20%5Cfrac%7Bx%7D%7Bt%7D)
![v_x = \frac{13.39}{2.75}](https://tex.z-dn.net/?f=v_x%20%3D%20%5Cfrac%7B13.39%7D%7B2.75%7D)
![v_x = 4.87 m/s](https://tex.z-dn.net/?f=v_x%20%3D%204.87%20m%2Fs)
Answer:
By a factor of 1/4.
Explanation:
The impulse force that applies to an object undergoing rapid deceleration just before coming to a stop on the ground is given by the following formula,
in which
,
represent the change in momentum and the time taken for that change.
If one increases the time that is taken for the momentum change (which remains constant for this situation) by a factor 4 and if that new force is represented by
, the following manipulation confirms the answer to this question.
![\begin{aligned}\\\small F_1 &=\small \frac{\Delta (mV)}{4\Delta t}\\\\&=\small \frac{1}{4}\times\bigg[\frac{\Delta (mV)}{\Delta t}\bigg]\\\\&=\small \frac{1}{4}F\end{aligned}](https://tex.z-dn.net/?f=%5Cbegin%7Baligned%7D%5C%5C%5Csmall%20F_1%20%26%3D%5Csmall%20%5Cfrac%7B%5CDelta%20%28mV%29%7D%7B4%5CDelta%20t%7D%5C%5C%5C%5C%26%3D%5Csmall%20%5Cfrac%7B1%7D%7B4%7D%5Ctimes%5Cbigg%5B%5Cfrac%7B%5CDelta%20%28mV%29%7D%7B%5CDelta%20t%7D%5Cbigg%5D%5C%5C%5C%5C%26%3D%5Csmall%20%5Cfrac%7B1%7D%7B4%7DF%5Cend%7Baligned%7D)
Here
is the force that was applied to the object previously.
#SPJ4
geyser.........................................
Answer:
Renewable Resource Hydropower is renewed by the Earth's hydrologic cycle. Water has also been considered renewable, but overpumping of groundwater is depleting aquifers, and pollution threatens the use of many water resources, showing that the consequences of resource use are not always simple depletion.For low-mass stars (left hand side), after the helium has fused into carbon, the core collapses again. As the core collapses, the outer layers of the star are expelled. A planetary nebula is formed by the outer layers. The core remains as a white dwarf and eventually cools to become a black dwarf. inexpensive compared to coal ... o Two types of coal—low rank (pollutes more), and high rank.
Explanation: