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ololo11 [35]
2 years ago
7

In a basketball game, a player shoots a jump shot. Which force actually causes the player to jump? the player pushing down on th

e floor the push of the ball on the floor the floor pushing up on the player the push of the floor on the ball\
Physics
2 answers:
Gemiola [76]2 years ago
4 0

Answer:  the player pushing down on the floor

Explanation:

Zigmanuir [339]2 years ago
4 0

Answer:In a basketball game, a player shoots a jump shot.

Which force actually causes the player to jump?

   the floor pushing up on the player YES

   the player pushing down on the floor NO

   the push of the ball on the floor NO

   the push of the floor on the ball NO

Explanation:

the floor pushing up on the player

this is for k12 8th grade science test

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Debora [2.8K]
Thinking the small glass bead as a single point charge, the electric field generated by it is given by
E(r) = k_e  \frac{Q}{r^2}
where
k_e = 8.99 \cdot 10^9 N m^2 C^{-2} is the Coulomb's constant
Q=8.0 nC=8.0 \cdot 10^{-9} C is the charge of the bead
r=3.0 cm=0.03 m is the distance at which we calculate the field.

Using these data, we find:
E=(8.99 \cdot 10^9 N m^2 C^{-2} ) \frac{(8.0 \cdot 10^{-9} C}{0.03 m)^2}=8.0 \cdot 10^4 N/C
6 0
2 years ago
A car start from rest and reached with a speed of 20m/s in 9seconds calculate the acceleration of the car and calculate the disp
Snezhnost [94]

Hi there!

Acceleration:

a = Δv / Δt, so:

a = 20/9 ≈ 2.22 m/s²

Displacement:

We can use the equation Δd = v₀t + 1/2at² to solve. (Initial velocity is 0).

Δd = 1/2at²

Plug in the acceleration and time:

Δd = 1/2(2.22)(9)² ≈ 89.91 m

5 0
2 years ago
A biker can ride at 12 m/s on a level road when there is no wind and at 7.5 m/s on a level road when there is a head wind of 5 m
alexandr402 [8]

Answer:

The answer is "1.94 \ m^2".

Explanation:

Formula:

F= \frac{1}{2} \times C_D \times density \times area \times  velocity^2\\\\Power (P) = F \times velocity \\\\P = \frac{C_D}{2} \times density \times area \times  velocity^3\\

Given value:

\ P = 10.25 \ W \\\\\ density = 1.2 \ kg/m^3 \\\\\ velocity= 2.5 \\\\

10.25 = \frac{C_D A}{2} \times 1.2 \times 2.5^3\\\\C_D A= \frac{10.25 \times 2 }{1.2 \times 2.5^3}\\\\C_D A = 1.94 m^2\\

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2 years ago
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vazorg [7]

Answer:

it is D

Explanation:

cause i took the test

3 0
3 years ago
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Tatiana [17]
C. has to be right, also its the only one that makes sense.
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