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astra-53 [7]
3 years ago
13

Which group of solid figures have curved surfaces​

Mathematics
1 answer:
Burka [1]3 years ago
4 0

Answer:

manyuhsjshd djdjjdbejsjjdue

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Help pleaseeeeeeeeeeee
Yuliya22 [10]

Answer:

x = 1

GF = 12

GH = 15

FH = 3

Step-by-step explanation:

G___F___H

GH = GF + FH

11x +4 = ( 3x +9) + (5x-2)

11x+4= 8x + 7

11x - 8x = 7-4

3x = 3

x =3/3

x = 1

GF = 3x + 9 = 3(1)+9=3+9=12

GH = 11x +4= 11(1)+4=11+4 = 15

FH = 5x - 2 = 5(1) - 2 = 5 - 2 = 3

I hope I helped you^_^

5 0
3 years ago
Is this answer correct ?
Sever21 [200]
Yes you are correct!
6 0
4 years ago
Read 2 more answers
Prove the divisibility of the following numbers:
Brut [27]

Answer:

Step-by-step explanation:

To prove divisibility, we need to factor the divident such that one of its factors matches the divisor.

(I use the notation x|y to denote that x divides y)

(A)

75^{30}|45^{45}\cdot15^{15}\\45^{45}\cdot15^{15}=3^{45}\cdot 15^{45}\cdot 15^{15}=\\=3^{45}\cdot 15^{60}=3^{45}\cdot 15^{30}\cdot 15^{30}=3^{45}\cdot (3\cdot5)^{30}\cdot 15^{30}=\\=3^{45}\cdot 3^{30}\cdot(5\cdot 15)^{30}=3^{45}\cdot 3^{30}\cdot(75)^{30}\\\implies\\75^{30}|3^{45}\cdot 3^{30}\cdot75^{30}

(B)

72^{63}|24^{54}\cdot 54^{24}\cdot2^{10}\\24^{54}\cdot 54^{24}\cdot2^{10}=(2^{162}\cdot 3^{54})\cdot(2^{24}\cdot 3^{72}) \cdot 2^{10}\\=2^{196}\cdot 3^{126}

In this case, it is easier to also factor the divisor to primes:

72^{63}=2^{189}\cdot 3^{126}

Both of these factor must be matched in the dividend in order to prove divisibility, and that indeed turns out to be true:

2^{189}\cdot 3^{126}|2^{196}\cdot 3^{126}\implies\\2^{189}|2^{196}\,\,\mbox{and}\,\,3^{126}|3^{126}

6 0
3 years ago
(x + 1) (x+8) multiply binomials and put in standard form.
Kobotan [32]

Answer:

x² + 9x + 8

Step-by-step explanation:

Step 1: FOIL

x² + 8x + x + 8

Step 2: Combine like terms

x² + 9x + 8

6 0
3 years ago
Read 2 more answers
1/2=4p what does p equal
disa [49]
P = what times 4 equals 1/2 = 1/8
3 0
3 years ago
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