Question

April does 1800 J of work to get a canoe moving from rest. April and the canoe have a mass of 70 kg. a. What is the kinetic energy of April and the canoe after she does the work?

Answer 1

E = (1/2)mv²

1800 = (1/2)(70)v²

Solving for v²

1800(2)/70 = v²

v² = 55.714

√v² = √55.714

v = ~7.46 m/s

Answer 2

Answer:

Kinetic energy = 1800 J

Explanation:

As per work energy theorem we know that the total work done on the system is always equal to the change in kinetic energy of the system

So we can say it as

$W_{net} = KE_f - KE_i$

here we can say that initially it starts from the rest state so the initial kinetic energy is given as

$KE_i = 0$

now from above equation we can say

$W_{net} = KE_f - 0$

so final kinetic energy must be equal to net work done on it

kinetic energy = 1800 J