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Lina20 [59]
3 years ago
13

Compare and contrast the causes and effects of ocean-continent

Chemistry
1 answer:
d1i1m1o1n [39]3 years ago
7 0

Answer:seen below

Explanation:

The effects of an ocean-ocean subduction zone are the same as those of an ocean-continent subduction zone in that, the subduction zone where an oceanic plate subducts beneath another oceanic plate are the same as a continent-ocean subduction zone.

They oceanic plate and the continental plate are both convergent zones, but when an oceanic plate converges with a continental plate, the oceanic plate is forced underneath the continental plate this is because oceanic crust is thinner and denser than the continental crust. The difference is that the volcanic arc formed will be a set of islands known as an island arc.

If two plates meet at a convergent plate boundary both are of oceanic crust, the older, denser plate will subduct beneath the less dense plate into a trench, resulting in earthquakes.

Finally, When two continents meet head-on, neither is subducted under, this is because the continental rocks are relatively light and are like two colliding icebergs they resist downward motion. Instead, the crust tends to buckle and be pushed upward or sideways.

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wind and water erosion

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Thirty grams of lead oxide and fifteen grams of ammonia react completely to produce solid lead, nitrogen gas, and liquid water.
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45 g  Thirty grams of lead oxide and fifteen grams of ammonia react completely to produce solid lead, nitrogen gas, and liquid water.

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If 10.62 mL of a standard 0.3330 M KOH solution reacts with 98.20 mL of CH3COOH solution, what is the molarity of the acid solut
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Answer:

0.036 M of CH_{3} COOH

Explanation:

It is an example of acid-base neutralization reaction.

KOH  + CH_{3} COOH  ----> CH_{3} COO^{-} K^{+}   +   H_{2}O

Base           Acid                           Salt                                    

When two component react then the number of moles of both the component should be same, therefore the number of moles and acids and bases should be the same in the following .

Molarity= \frac{\textrm{No. of Moles}}{\textrm{Volume of the Particular Solution}}

No.of moles= Molarity × Volume of the Particular Solution

Therefore,

M_{1}V_{1} =M_{2}V_{2}------------------------------(1)

where

M_{1}= Molarity of Acid

V_{1}= Volume of Acid

M_{2}= Molarity of Base

V_{2}= Volume of Base

M_{1}=0.3330 M

V_{1}=10.62 mL

V_{2}=98.2 mL

M_{2}=??(in M)

Plugging in Equation 1,

0.3330 × 10.62 =M_{2}  × 98.2  

M_{2}=\frac{0.3330*10.62}{98.2}

M_{2}=0.036 M

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3 years ago
Consider the molecules in the two proposed systems. How are they the same and how are they different?
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Molecules may be similar or different on the basis of size, shape, structure and chemical composition.

<h2>Similarities and differences</h2>

Two molecules can be considered similar or different on the basis of size, shape, structure and chemical composition. The molecules in the two proposed systems are consider the same when they are similar in size, shapes, structure and chemical composition.

While on the other hand, the molecules is considered different when they have different structure and chemical composition so we can say that molecules may be similar or different on the basis of size, shape, structure and chemical composition.

Learn more about molecules here: brainly.com/question/26044300

Learn more: brainly.com/question/26268787

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