When an object is dropped what happens to potential and kinetic energy as it falls
1 answer:
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Answer:
3.8 x 10^10 m/s^2
Explanation:
Charge, q = 2 e = 2 x 1.6 x 10^-19 C = 3.2 x 10^-19 C
Electric field strength, E = 790 N/C
mass of helium nucleus, m = 6.645 x 10^-27 Kg
the force due to electric filed on a charge particle is given by
F = q x E
Where, q be the charge on the charged particle and E be the strength of electric field.
By substituting the values
F = 3.2 x 10^-19 x 790
F = 2528 x 10^-19 N
According to the Newton's second law
F = m x a
Where, me be the mass and a be the acceleration
By substituting the values
a = 3.8 x 10^10 m/s^2