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3 years ago

Select all the correct answers.

Chemistry

1 answer:

Lera25 [3.4K]3 years ago

6 0

The correct answers :

It increases with a decrease in the concentration of H₂(g).

It decreases with an increase in the concentration of S₂(g).

It decreases with an increase in the concentration of H₂(g).

<h3 /><h3>Further explanation</h3>

Forward reaction : rate to form product

In equilibrium :

The product decreases ⇒ system will move from left to right(forward reaction)

The product increases ⇒ system will move from right to left(reverse reaction)

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The Gibbs free-energy of a reaction predicts the spontaneity or feasibility of a given chemical reaction.

Given the standard Gibbs free energy changes:

Phosphocreatine → creatine + Pi, ∆G° = –43.0 kJ/mol ...(1)

ATP → ADP + Pi , ∆G° = –30.5 kJ/mol ....(2)

Now to calculate the Gibbs free-energy of the given chemical reaction: Phosphocreatine + ADP → creatine + ATP; the equation (2) is reversed to give:

ADP + Pi → ATP, ∆G° = + 30.5 kJ/mol ...(3)

Now the equation (3) and (1) are added, to give:

Phosphocreatine + ADP + Pi→ creatine + ATP + Pi

⇒ Phosphocreatine + ADP → creatine + ATP

Therefore, to calculate the Gibbs free-energy of the reaction, the standard Gibbs free energy changes of the equations (1) and (3) are added similarly:

Gibbs free-energy of the reaction: ∆G° = (–43.0 kJ/mol) + ( + 30.5 kJ/mol) = (–12.5 kJ/mol)

Therefore, the Gibbs free-energy of the reaction = (–12.5 kJ/mol)

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