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Ulleksa [173]
2 years ago
8

What is the name of the polygon that has 4 congruent sides?

Mathematics
1 answer:
olya-2409 [2.1K]2 years ago
4 0

Square (D)

PLS GIVE BRAINLIEST THANKS

GL WITH THE REST OF UR WORK

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Leviafan [203]
The top row on the right:)

this number line includes any number to the left of 6 including 6!
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3 years ago
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To purchase $12,900 worth of machinery for her business, Melissa made a down payment of $2100 and took out a business loan for t
Ierofanga [76]

Answer:

a) $13588.08

b) $688.08

Step-by-step explanation:

Melissa had to purchase $12,900 worth of machinery for her business.

She made a down payment of $2100 and after that made monthly payments of $478.67 for the business loan for the rest.

Given that after years of paying monthly payments of $478.67, she finally paid off the loan.

Assume that she took 2 years to repay the loan.

a) Therefore, the total amount Melissa ended up paying for the machinery was $[2100 + (478.67 × 24)] = $13588.08 (Answer)

b) Therefore, the amount of interest that Melissa pay on the loan is $(13588.08 - 12900) =$688.08. (Answer)

4 0
3 years ago
A circle has a radius of 3. An arc in this circle has a central angle of 20°. What is the length of the arc? Either enter an exa
Semenov [28]

Answer:

\frac{\pi  }{3}

2 * \pi * 3  * \frac{20}{360}

120\pi/360 = \frac{\pi  }{3}

Step-by-step explanation:

5 0
2 years ago
Resistors are labeled 100 Ω. In fact, the actual resistances are uniformly distributed on the interval (95, 103). Find the mean
Zinaida [17]

Answer:

E[R] = 99 Ω

\sigma_R = 2.3094 Ω

P(98<R<102) = 0.5696

Step-by-step explanation:

The mean resistance is the average of edge values of interval.

Hence,

The mean resistance, E[R] = \frac{a+b}{2}  = \frac{95+103}{2} = \frac{198}{2} = 99 Ω

To find the standard deviation of resistance, we need to find variance first.

V(R) = \frac{(b-a)^2}{12} =\frac{(103-95)^2}{12} = 5.333

Hence,

The standard deviation of resistance, \sigma_R = \sqrt{V(R)} = \sqrt5.333 = 2.3094 Ω

To calculate the probability that resistance is between 98 Ω and 102 Ω, we need to find Normal Distributions.

z_1 = \frac{102-99}{2.3094} = 1.299

z_2 = \frac{98-99}{2.3094} = -0.433

From the Z-table, P(98<R<102) = 0.9032 - 0.3336 = 0.5696

5 0
3 years ago
Find the mean of 1,0,10,7,13,2,9,15,0,3
svet-max [94.6K]
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