What is the relationship between Hectare and cubic meter<br>

When the liquid line is restricted, the supply of refrigerant to the metering device is reduced. What is the effect on suction p

Nimfa-mama [501]

Answer:

The suction pressure decreases and the superheat increases when the liquid line is restricted and the supply of refrigerant to the metering device is reduced.

Explanation:

1. The five components of refrigeration are:

Fluid refrigerant
Compressor
Condenser coil
Evaporator coil
Expansion device.

The compressor limits the vapor released by the refrigerant. This

causes a rise in pressure (in refrigerant), which then pushes the

vapor into the coils on the outside of the refrigerator.

2. Now when the cooler air meets the warm gas present in the coils, it

gets converted into liquid form.

3. Thus, when the liquid form is at high pressure, the refrigerant then

cools down as it flows through the coils placed in the fridge ( in both

freezing and normal sections).

4. The refrigerant also absorbs the warm air present in the fridge, which

causes it to evaporate and flow back through the compressor and the

cycle repeats in the same form.

Thus, when the liquid line is restricted and the supply of refrigerant to the metering device is reduced it causes a decrease in suction pressure and an increase in superheat.

Learn more about refrigeration here:

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8 0

2 years ago

In April 1974, Steve Prefontaine completed a 10 km race in a time of 27 min, 43.6 s. Suppose "Pre" was at the 8.13 km mark at a

SOVA2 [1]

Answer: $0.084 m/s^2$

Explanation:

Given

Total time=27 min 43.6 s=1663.6 s

total distance=10 km

Initial distance $d_1=8.13 km$

time taken=25 min =1500 s

initial speed $v_1=\frac{8.13\times 1000}{25\times 60}=5.6 m/s$

after 8.13 km mark steve started to accelerate

speed after 60 s

$v_2=v_1+at$

$v_2=5.6+a\times 60$

distance traveled in 60 sec

$d_2=v_1\times 60+\frac{a60^2}{2}$

$d_2=336+1800 a$

time taken in last part of journey

$t_3=1663.6-1560=103.6 s$

distance traveled in this time

$d_3=v_2\times t_3$

$d_3=\left ( 5.6+a\times 60\right )103.6$

and total distance $=d_1+d_2+d_3$

$10000=8.13\times 1000+336+1800 a+\left ( 5.6+a\times 60\right )103.6$

$1870=336+1800 a+\left ( 5.6+a\times 60\right )103.6$

$a=0.084 m/s^2$

5 0

3 years ago

In which condition the acceleration of a moving vehicle become zero

Alekssandra [29.7K]

Explanation:

When,the vehicle has uniform velocity, it's acceleration becomes zero

4 0

3 years ago

a woman walks south at a speed of 2.0mph for 60 minutes. She then turns around and walks north at a distance of 3000m in 25 minu

TiliK225 [7]

When a woman walks south at a speed of 2.0mph for 60 minutes. She then turns around and walks north at a distance of 3000m in 25 minutes. then the woman's average speed during her entire motion would be 73.15 meters /minute.

<h3>What is speed?</h3>

The total distance covered by any object per unit of time is known as speed.

the mathematical expression for speed is given by

speed = total; distance /total time

As given in the problem a woman walks south at a speed of 2.0mph for 60 minutes

60 min = 1 hour

1 mile = 1.60934 km

The distance covered by her southwards = speed ×time

=2 mph × 60 minutes

= 3.218 km

She then turns around and walks north at a distance of 3000m in 25 minutes

The distance covered northward is 3000m

speed = total distance /total time

=(3218 +3000) /(60+25)

=73.15 meters /minutes

Thus, The average speed of the woman would be 73.15 meters /minute.

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8 0

2 years ago

An object weighs 32 newtons. What is its mass if a gravitometer indicates that g = 8.25 m/s?

Elan Coil [88]

Explanation:

weight=mass×g

32=mass×8.25

mass=

$\frac{128}{33} = 3.878$ kg

8 0

3 years ago

What is the relationship between Hectare and cubic meter​

What is the relationship between Hectare and cubic meter