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3 years ago

In loading a lorry, a man lifts boxes each of weight 100N through a height of 1.5m.

Physics

1 answer:

liq [111]3 years ago

5 0

Answer:

The amount of work done in order to lift the box is $150\ Joule$

Explanation:

Given the weight of each box is $100N$

And the man lifts boxes at a height of $1.5m$

We need to find the amount of work done.

The amount of work done is the product of applied force $F$ that causes the displacement $d$ .

In our problem force is $100N$ and displacement is $1.5m$ .

Now, work done

$=force\times displacement\\=100\times1.5\\=150\ Joule$

So, the amount of work done in order to lift the box is $150\ Joule$

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3 years ago

A 200 g load attached to a horizontal spring moves in simple harmonic motion with a period of 0.410 s. The total mechanical ener

defon

Complete question:

A 200 g load attached to a horizontal spring moves in simple harmonic motion with a period of 0.410 s. The total mechanical energy of the spring–load system is 2.00 J. Find

(a) the force constant of the spring and (b) the amplitude of the motion.

Answer:

(a) the force constant of the spring = 47 N/m

(b) the amplitude of the motion = 0.292 m

Explanation:

Given;

mass of the spring, m = 200g = 0.2 kg

period of oscillation, T = 0.410 s

total mechanical energy of the spring, E = 2 J

The angular speed is calculated as follows;

$\omega = \frac{2\pi}{T} \\\\\omega = \frac{2\pi}{0.41} \\\\\omega = 15.33 \ rad/s$

(a) the force constant of the spring

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E = ¹/₂kA²

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