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ratelena [41]
3 years ago
15

In loading a lorry, a man lifts boxes each of weight 100N through a height of 1.5m.

Physics
1 answer:
liq [111]3 years ago
5 0

Answer:

The amount of work done in order to lift the box is 150\ Joule

Explanation:

Given the weight of each box is 100N

And the man lifts boxes at a height of 1.5m

We need to find the amount of work done.

The amount of work done is the product of applied force F that causes the displacement d.

In our problem force is 100N and displacement is  1.5m.

Now, work done

=force\times displacement\\=100\times1.5\\=150\ Joule

So, the amount of work done in order to lift the box is 150\ Joule

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The metalloids are located on the right side of the periodic table in a "step-like" arrangement.

All of the possible metalloids are:

boron (B), silicon (Si), germanium (Ge), arsenic (As), antimony (Sb), tellurium (Te), and polonium (Po)

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B. relative humidity
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Peter does 3,000 joules (J) of work by moving an object 40 meters (m). What is the force that Peter applies to the object? A 75
Papessa [141]

The force that peter applies to the object of distance 40m is 75N.

<h3>HOW TO CALCULATE FORCE</h3>

The force applied to an object can be calculated by dividing the work done on the object by the distance moved. That is;

Force = Work done ÷ distance

According to this question, the work done is 3000 joules while the distance moved is 40m. The force is calculated as follows:

Force = 3000J ÷ 40m

Force = 75N

Therefore, the force that peter applies to the object of distance 40m is 75N.

Learn more about force at: brainly.com/question/26115859

4 0
2 years ago
An infinite sheet carries a uniform, positive charge per unit area. The electric field produced by the sheet is represented by p
nexus9112 [7]

Complete Question

An infinite sheet carries a uniform, positive charge per unit area. The electric field produced by the sheet is represented by parallel lines drawn with a density N lines per m2 that are perpendicular to and away from the sheet. The charge per unit area on the sheet is doubled. How should the density of the electric field lines be changed?

A It should stay the same

B  It should be quadrupled.

C It should be quintupled

D It should be doubled.

E It should be tripled

Answer:

Option D is the correct option

Explanation:

Generally electric field is mathematically represented as

        E =  \frac{\sigma}{\epsilon_o}

Where \sigma is the charge per unit area (Charge density )

From the question we are told that \sigma is doubled hence the

     E =  \frac{2 \sigma }{\epsilon_o}    

Looking the equation above we see that the value of the electric field will also double given that it is directly proportional to the charge density

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3 years ago
What can you conclude about the direction of motion of the object after the application of the additional force?
Anna35 [415]

It will move in the direction of applied force following the law of newton that is an object is stationary until an external force is applied then it moves in direction of force

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